We will have to use completing the square here.
y = x^2 + 2x - 1
set to 0
x^2 + 2x - 1 = 0
x^2x + 2x = 1
now, halve the coefficient of the linear term ( 2x ), square it and add it to both sides
x^2 + 2x + 1 = 1 + 1
factor the left side; add up right side
(x + 1)^2 = 2
subtract 2 from both sides
(x + 1)^2 - 2 = 0
(-1,-2) is the vertex
my TI-84 confirms this from original equation
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
The given equation is not that of a parabola.
Question can be taken as multiple meanings. Please see discussion.
when you have y=+/-x2 +whatever, the parabola opens up y=-(x2 +whatever), the parabola opens down x=+/-y2 +whatever, the parabola opens right x=-(y2 +whatever), the parabola opens left so, your answer is up
7
The vertex has a minimum value of (-4, -11)
It is the parabola such that the coordinates of each point on it satisfies the given equation.
(-3, -5)
The vertex of the positive parabola turns at point (-2, -11)
The minimum value of the parabola is at the point (-1/3, -4/3)
It is a parabola with its vertex at the origin and the arms going upwards.
20 and the vertex of the parabola is at (3, 20)
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
The given equation is not that of a parabola.
(6, 40) and (-1, 5)
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).