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The most famous force that is always perpendicular to the displacement is the force exerted by a static magnetic field on a moving charged object.
Calling q the charge of the moving object, v the object velocity vector and B the magnetic induction filed, the force F exerted by the magnetic field on the moving object can be expressed as
F = q v X B
where X indicates vector product. Since the displacement ds in an infinitesimal time dt is proportional to the velocity by
ds = v dt
the property of the vector product itself to be perpendicular to both the factors produces that the force is always perpendicular to the displacement, independently from the displacement direction.
Interesting enough, the force F is not conservative (it does not have a potential associated to it), but the work exerted on the moving charge is always equal to zero. As a matter of fact, the infinitesimal work dW is given by
dW=F.ds
where the point represents scalar product. Since the scalar product is zero if the factors are orthogonal, dW is always zero. The intimate meaning of this strange property is that, being the acceleration always parallel to the force for the second Newton principle, the acceleration induced by the magnetic field is always orthogonal to the velocity so that it changes the velocity direction (induces a curvature in the particle trajectory) but not the velocity module that is directly related to the moving object kinetic energy.
What else can I help you with?
What 2 things does the moment of a force depend on?
What two factors must be known in order to calculate the moment of a force? Torque = Force * distance Torque and distance must be perpendicular to each other If not you must determine the portion of the torque that is perpendicular.
When body moves in a circular path how much work is done by the body?
Zero. This is because when a body when around in a circle, a centripetal force acts on the particle to keep it at that fixed distance from the centre. At each point, the force and the displacement are perpendicular to each other. Hence no work is done. The answer is NOT Zero! A Force is required in the direction of motion around the circle. At every point (an infinite number of them) there must be a Force PERPENDICULAR to the Centrifugal and Centripetal Forces or the object would not move. Therefore the amount of work done is the product of that FORCE times the circumference of the circular path, if only considering one revolution.
How is buoyant force and displacement related?
buoyant force is the result of the displacement of the fluid an object is in. if a fluid is displaced by the volume of an object, the weight of the fluid being displaced is pushing up on that object
160j of work was needed in order to move an object 8m across the floor what was the force in N that was needed to do this job?
Work = Force * Displacement. Therefore Force = Work / Displacement = 160 J / 8 m = 20 N (Note that the force and the displacement have to be in the same direction, or else the components of either of them will have to be calculated in the direction of the other)
What is a force And what are some examples of force?
A force is a push or pull on an object some ex are friction
Why is it that no work is done when the force and the displacement are perpendicular to each other?
When a force and displacement are perpendicular to each other, no work is done because the force is not acting in the same direction as the displacement. Work is defined as the product of force and displacement in the direction of the force, so when they are perpendicular, the force does not contribute to the displacement and no work is done.
When force is perpendicular to the direction of motion no work is done ture or false?
True. When the force is perpendicular to the direction of motion, no work is done because work is the product of force and displacement in the direction of the force. Since there is no displacement in the direction of the force, no work is done.
When force is and what direction of motion no work is done?
When a force is perpendicular to the direction of motion, no work is done. This is because work is defined as the product of force and displacement in the direction of the force. If the force is perpendicular, then there is no displacement in the direction of the force and thus no work is done.
What are the conditions under which a force does no work?
A force does no work when there is no displacement of the object it is acting on, or when the force is perpendicular to the direction of motion. Another condition is when the force applied is zero, since work is the product of force and displacement.
How much work is done on a body of mass 1kg whirling on a circular path of radius 5m?
Zero, in this case acting force is perpendicular to the direction of displacement... Reason..... It is because here the angle is 90 degree and when there is an angle then the force is equal to F cos x * d= F *cos 90*0= 0 Therefore work done=0
When force is perpendicular to the direction of motion is work done?
No. At least not by the force that's perpendicular to the motion. When you push a baby stroller (or a car), you do work, but the force of gravity, downward and perpendicular to the motion, doesn't.
Can a centripetal force ever do work on an object. explain?
Centripetal force refers to the force that acts on a body moving in a circular path. It does not do work on an object because it acts perpendicular to the motion of the body. The work done on a rotating object is zero.
What 2 things does the moment of a force depend on?
What two factors must be known in order to calculate the moment of a force? Torque = Force * distance Torque and distance must be perpendicular to each other If not you must determine the portion of the torque that is perpendicular.
Why work done by centripetal force during half rotation is zero?
The centripetal force always acts perpendicular to the displacement of the object moving in a circular path. Since the work done is the product of force and displacement in the direction of force, and the displacement is perpendicular to the centripetal force, the work done by the centripetal force over a full rotation is zero.
What is the work done by a body moving along a circular path?
The work done by a body moving along a circular path is zero if the force is perpendicular to the direction of motion, such as in the case of centripetal force. This is because the displacement is perpendicular to the force. If there is a component of the force in the direction of the motion, work is done, calculated as the dot product of the force and displacement vectors.
If you exert a force you will always do work in the scientific sense.?
Not necessarily. Work in the scientific sense is only done when the force causes displacement in the direction of the force. If the force and displacement are perpendicular, no work is done. Work is defined as the product of the force applied and the distance moved in the direction of that force.
When is workdone by force is zero?
Work done by a force is zero when the force is applied perpendicular to the direction of motion of the object. Another scenario is when the force is applied but there is no displacement of the object.
