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The most famous force that is always perpendicular to the displacement is the force exerted by a static magnetic field on a moving charged object.
Calling q the charge of the moving object, v the object velocity vector and B the magnetic induction filed, the force F exerted by the magnetic field on the moving object can be expressed as
F = q v X B
where X indicates vector product. Since the displacement ds in an infinitesimal time dt is proportional to the velocity by
ds = v dt
the property of the vector product itself to be perpendicular to both the factors produces that the force is always perpendicular to the displacement, independently from the displacement direction.
Interesting enough, the force F is not conservative (it does not have a potential associated to it), but the work exerted on the moving charge is always equal to zero. As a matter of fact, the infinitesimal work dW is given by
dW=F.ds
where the point represents scalar product. Since the scalar product is zero if the factors are orthogonal, dW is always zero. The intimate meaning of this strange property is that, being the acceleration always parallel to the force for the second Newton principle, the acceleration induced by the magnetic field is always orthogonal to the velocity so that it changes the velocity direction (induces a curvature in the particle trajectory) but not the velocity module that is directly related to the moving object kinetic energy.
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What 2 things does the moment of a force depend on?
What two factors must be known in order to calculate the moment of a force? Torque = Force * distance Torque and distance must be perpendicular to each other If not you must determine the portion of the torque that is perpendicular.
When body moves in a circular path how much work is done by the body?
Zero. This is because when a body when around in a circle, a centripetal force acts on the particle to keep it at that fixed distance from the centre. At each point, the force and the displacement are perpendicular to each other. Hence no work is done. The answer is NOT Zero! A Force is required in the direction of motion around the circle. At every point (an infinite number of them) there must be a Force PERPENDICULAR to the Centrifugal and Centripetal Forces or the object would not move. Therefore the amount of work done is the product of that FORCE times the circumference of the circular path, if only considering one revolution.
How is buoyant force and displacement related?
buoyant force is the result of the displacement of the fluid an object is in. if a fluid is displaced by the volume of an object, the weight of the fluid being displaced is pushing up on that object
160j of work was needed in order to move an object 8m across the floor what was the force in N that was needed to do this job?
Work = Force * Displacement. Therefore Force = Work / Displacement = 160 J / 8 m = 20 N (Note that the force and the displacement have to be in the same direction, or else the components of either of them will have to be calculated in the direction of the other)
If the force moving an object points at least partially in the opposite direction of the object's motion what is the work considered to be?
Work = Force * displacement * Cosine of the angle between Force and displacement.. Here, that angle would be 180 degrees Cos 180 degree = -1 Hence work will be negative Work (W).
What 2 things does the moment of a force depend on?
What two factors must be known in order to calculate the moment of a force? Torque = Force * distance Torque and distance must be perpendicular to each other If not you must determine the portion of the torque that is perpendicular.
What are the quantities on which the amount of work done depends and How are they related to work?
work depends on:FORCE and DISPLACEMENT. it is directly proportional to both of them. work can be calculated by the product of force and displacement. if displacement is in a certain direction to the applied force then work done is calculated by force*displacement cos(angle). work done becomes 0when:- *displacement is 0 or the initial point and final point are the same. *displacement is in perpendicular direction to force applied.
What is work done by a coolie walking on a horizontal platform with a load on his head?
The displacement of the load is perpendicular to the direction of force therefore work done by the coolie against the force of gravity is zero.
Work is the product of and an object's displacement?
It is a product of force and displacement: Work = force x displacement
Why no work is done when force is perpendicular to the body?
How can a force be perpendicular to a point?! Surely you wanted to ask "Why no work is done when force is perpendicular to the direction of the displacement of the body?". This finds a simple answer in the definition of work: work done by a force F is defined asW := ∫ Fdr,where r is the position of the particle (that is, of the point of the body the force acts on), and hence dr is the direction of the displacement of the particle. From the definition, you immediatly see that if the angle between F and dris 90° (or, in general, (2n + 1)π/2, with n element of Z) the scalar product is Fdr = 0, and thus W = ∫0 = 0.
What is the work done when the direction of displacement and the direction of force acting on the body are perpendicular to each other?
according to physics it will be zero work W=F.S (dot product of force and displacement) from vector algebra W= F*S*cos ( angle between force and displacement) W = F * S * COS (90) BUT cos(90)= 0 so W=0
What is the definition of the word 'work' in physics?
The word 'work' in physics is defined as the transfer of energy from one material body to another. It is a body's displacement in space caused by an external force resulting in motion. If a force is applied but there is no displacement or motion, then no work is done. Also work is not done if a force is applied perpendicular to the body's displacement. Work is expressed in units such as joules or foot-pounds.
Can a centripetal force ever do work on an object. explain?
Centripetal force refers to the force that acts on a body moving in a circular path. It does not do work on an object because it acts perpendicular to the motion of the body. The work done on a rotating object is zero.
The application of a force through a distance?
Work = Force * displacement if the displacement and the force are parallel - work is positive if force and displacement are in the same direction, negative if they have opposite direction. At an angle Work = Force * displacement * cos(θ) where θ is the angle between the force and displacement vectors.
How much work is done by the centripetal force on a body along a circular path?
Zero. W = F* d cos (Theta) W = Tension * displacement * cos (90) The force is perpendicular to the objects motion (or displacement of the object) W = T * d * 0 W= 0
What are the examples of vectors?
Examples of vector quantity are displacement, velocity, acceleration, momentum, force, E-filed, B-field, torque, energy, etc.
What are the examples of vector?
Examples of vector quantity are displacement, velocity, acceleration, momentum, force, E-filed, B-field, torque, energy, etc.
