Two elements that form compounds that can be exceptions to the octet rule?

Answer 1

Boron and fluorine in the trivalent boron compound BF3 have only 6 electrons in the valence shell.

Oxygen and nitrogen in nitric oxide, NO, contain one or more atoms which have an odd number (one UNpaired '.' ) of electrons. Lewis dot structure |N.=O

Answer 2

Hydrogen and helium (which can only have 2 valence electrons) are exceptions to the octet rule.

So are elements in row three and beyond which can have expanded octet structures.

1. molecules, such as NO, with an odd number of electrons 2. molecules in which one or more atoms possess more than eight electrons, such as SF 6 and 3. molecules such as BCl 3, in which one or more atoms possess less than eight electrons.

Answer 3

There are many exceptions that could be applied to the octet rule. They could for example use a septet rule.

Answer 4

Hydrogen and Helium are the two elements that form compounds that are exceptions to the octet rule. This is because they can only have two valence electrons.

Answer 5

Good-faith

Hydrogen and helium only have one electron orbital which only hold two electrons so they follow the duet rule instead of the octet rule.

Answer 6

1. Molecules with an odd number of electrons

2. Molecules in which an atom has less than an octet

3. Molecules in which an atom has more than an octet

Answer 7

Hydrogen and helium. They can take a maximum of 2 electrons in the 1s orbital.

Answer 8

Hydrogen is one exception, as it's atoms only form bonds with two electrons. Boron is another exception. Boron has three valence electrons, [He]2s^2 2p^1.

Answer 9

Octet rules exceptions are: H, Be, B and sometimes S, P.

Answer 10

Hydrogen and Boron are the two I believe.