I guess you mean the standard quadratic equation, of the form ax^2 + bx + c = 0.There are three main algebraic methods, namely:
* Completing the square
* Using the quadratic formula
Since you want five, here are a few more, but they are usually not very convenient to use for this particular type of equation:
* Trial and error
* Graphic the equation
* Diverse iterative methods, such as Newton's method, etc.
1. Factoring 2. Quadratic formula
3. Plot the graph
4. Complete the square.
5. Numerical methods: "Trial and Improvement" or, for quicker results, the Newton-Raphson iteration.
There are several methods for solving quadratic equations, although some apply only to specific quadratic equations of specific forms. The methods include:Use of the quadratic formulaCompleting the SquareFactoringIterative methodsguessing
There are the following methods:quadratic formulacompleting the squaresfactorisingnumerical methods such as Newton-Raphsongraphical methods.
By using the quadratic equation formula or by completing the square
Using the quadratic equation formula is a method of solving quadratic equations.
Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by several methods including factoring, graphing, using the square roots or the quadratic formula. Completing the square will always work when solving quadratic equations and is a good tool to have. Solving a quadratic equation by completing the square is used in a lot of word problems.I want you to follow the related link that explains the concept of completing the square clearly and gives some examples. that video is from brightstorm.
you use the quadratic formula in math when the quadratic equation you are solving cannot be factored.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
Using the quadratic equation formula or completing the square
It is finding the values of the variable that make the quadratic equation true.
Here are some methods you can use:* Trial and error. This works especially well if the solution is a small integer. * Factoring. You must first write the equation in such a form that you have zero on the right. * Completing the square. * Using the quadratic formula. The last two methods work in all cases. The quadratic formula is easier to work with in the general case.
The quadratic formula is used all the time to solve quadratic equations, often when the factors are fractions or decimals but sometimes as the first choice of solving method. The quadratic formula is sometimes faster than completing the square or any other factoring methods. Quadratic formula find: -x-intercept -where the parabola cross the x-axis -roots -solutions
You will apply them when solving quadratic equations in which the quadratic expression cannot be factorised.
By knowing how to use the quadratic equation formula.
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
There are 5 existing methods in solving quadratic equations. For the first 4 methods (quadratic formula, factoring, graphing, completing the square) you can easily find them in algebra books. I would like to explain here the new one, the Diagonal Sum Method, recently presented in book titled:"New methods for solving quadratic equations and inequalities" (Trafford 2009). It directly gives the 2 roots in the form of 2 fractions, without having to factor the equation. The innovative concept of the method is finding 2 fractions knowing their Sum (-b/a) and their Product (c/a). It is very fast, convenient and is applicable whenever the given quadratic equation is factorable. In general, it is hard to tell in advance if a given quadratic equation can be factored. However, if this new method fails to find the answer, then we can conclude that the equation can not be factored, and consequently, the quadratic formula must be used. This new method can replace the trial-and-error factoring method since it is faster, more convenient, with fewer permutations and fewer trials.
In general, there are two steps in solving a given quadratic equation in standard form ax^2 + bx + c = 0. If a = 1, the process is much simpler. The first step is making sure that the equation can be factored? How? In general, it is hard to know in advance if a quadratic equation is factorable. I suggest that you use first the new Diagonal Sum Method to solve the equation. It is fast and convenient and can directly give the 2 roots in the form of 2 fractions. without having to factor the equation. If this method fails, then you can conclude that the equation is not factorable, and consequently, the quadratic formula must be used. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009) The second step is solving the equation by the quadratic formula. This book also introduces a new improved quadratic formula, that is easier to remember by relating the formula to the x-intercepts with the parabola graph of the quadratic function.
Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots or quadratic formula. Solving quadratic equations by completing the square will always work when solving quadratic equations-You can also use division or even simply take a GCF, set the quantities( ) equal to zero, and subtract or add to solve for the variable
The answer depends on the nature of the equation. Just as there are different ways of solving a linear equation with a real solution and a quadratic equation with real solutions, and other kinds of equations, there are different methods for solving different kinds of imaginary equations.
You'll typically use it when solving a quadratic equation - when factoring isn't obvious.
The 1st step would have been to show a particular quadratic equation in question.
Yes it is quite possible
That is what roots mean!
Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182
There are different methods of using quadratic functions depending on the equation.