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The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
166.153846 repeating degrees
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What is the sum of angles in a 28-sided polygon?
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
What is the sum of the interior angles of a 28-gon?
For an n-sided regular polygon, the sum of the interior angles is equal to 180 x (n - 2). In the case of a 28-sided polygon, this would be 180 x (28 - 2) = 180 x 26 = 4680 degrees.
What is the sum of the angle measures in a 26 gon?
The sum of the interior angles of any n-sided polygon is (2n - 4) right angles. Your example has n = 26 so total is (52 - 4) x 90 degrees, ie 48 x 90 which is4320 degrees.
What is the measure if each interior angle of a regular polygon with 15 sides?
Two ways to calculate the required angle. 1) Use the formula S = 2n - 4 right angles S is the sum of the interior angles of a polygon, n is the number of sides. Then, S = (2 x 15) - 4 = 26 right angles = 26 x 90 = 2340° So, each interior angle of a regular 15-sided polygon measures 2340/15 = 156° 2) Calculate the exterior angle and subtract from 180° to obtain the interior angle. Sum of exterior angles = 360° Each exterior angle measures, 360/15 = 24° Each interior angle measures, 180 - 24 = 156°
How many sides would the polygon have if the sum of interior angles is 4320 degrees?
If the polygon has n sides, then sum of interior angles = (n-2)*180 = 4320 so (n-2) = 4320/180 = 24 and so n = 24+2 = 26 sides.
What is the sum of the interior angles of a 26 sided polygon?
4,320° is.
What is the sum of angles in a 28-sided polygon?
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
What is the measure of the interior angle sum of a 15 sided polygon?
Sum of interior angles of any n-sided polygon is (2n - 4) right angles ie 26 x 90 which is 2340 degrees.
What is the sum of the interior angles of a 28-gon?
For an n-sided regular polygon, the sum of the interior angles is equal to 180 x (n - 2). In the case of a 28-sided polygon, this would be 180 x (28 - 2) = 180 x 26 = 4680 degrees.
What is the interior angle of a regular 26 sided polygon?
4320
What is the total interior angle measurement of a 15 sided polygon?
90 x (2 x 15 - 4) ie 90 x 26 = 2340o. The sum of the interior angles of an n-sided polygon always is 90 x (2n - 4) degrees
How many sides does a 4320 degree polygon have?
Search nyo sa googLe. Hahahaha :P PEACE TAYOImproved Answer:-A 26 sided polygon has interior angles that add up to 4320 degrees
What is the answer to this Find the sum of the interior angles of a polygon with 26 sides?
(26-2)*180 = 4320 degrees
What is the interior angle of a 28 sided polygon?
sum of interior angles of a regular polygon = (n-2) x 180 degrees, where n = number of sides. Each interior angle - sum of exterior angles / the total number of angles (and there are the same number of angles as sides, so you can use sum / n) = ((28-2)*180)/28) = (26*180 / 28) = 4680 / 28 = 167.1429 degrees
What is the sum of the angle measures in a 26 gon?
The sum of the interior angles of any n-sided polygon is (2n - 4) right angles. Your example has n = 26 so total is (52 - 4) x 90 degrees, ie 48 x 90 which is4320 degrees.
How many sides does a polygon have if the interior angle is 4320?
If the interior angles add up to 4320 degrees then it will have 26 sides
How many sides does a polygon have if the sum of the interior angles equal 4320?
It is: (4320+360)/180 = 26 sides
