Evenly divided 50:50
50%
The odds of guessing seven correct numbers in a typical lottery with 49 numbers is approximately 1 in 85 million. This calculation assumes that each number has an equal chance of being selected.
25%
Each guess has a 25% chance of being correct and a 75% chance of being wrong. Guessing right or wrong on one question does not affect the odds on the next one.
That depends on what the range of the guess is and whether you mean three consecutive times. Example : for guessing a number between 1 and 10 inclusive (10 numbers) the odds are 1 in 10 for each guess, or 0.1. To guess it correctly twice in a row the odds would be 0.1 x 0.1 or (0.1)², which is .01, or one in a hundred. To guess it correctly three times in a row, the odds would be 0.1 x 0.1 x 0.1 or (0.1)³, which is .001 or one in a thousand. It is the range or numbers raised to the power of the number of required correct consecutive guesses. Another example: guess a number between one and fifty inclusive twice in a row. The formula would be : odds=1/(50)², which is 1/2500 or one in 2500.
Unless you're a very indecisive personality, the ease or difficulty of picking a number shouldn't have anything to do with what size group of numbers you're asked to pick it out of. But if you're trying to guess what number somebody else is thinking of, then your chance of guessing his number between 1 - 5 correctly is double the chance of guessing his number between 1 - 10 correctly. Between 1 - 5: Your chance of guessing his number is 20%, or 4 to 1 odds against. Between 1 - 10: Your chance of guessing his number is 10%, or 9 to 1 odds against.
6 to 1. (That is, 6 incorrect to 1 correct.) This is equaivalent to a probability of 1/7 or a 14% chance of guessing the correct answer.
The odds of guessing seven correct numbers in a typical lottery with 49 numbers is approximately 1 in 85 million. This calculation assumes that each number has an equal chance of being selected.
7 to 1
7:1
25%
Each guess has a 25% chance of being correct and a 75% chance of being wrong. Guessing right or wrong on one question does not affect the odds on the next one.
Well, there are 12 different months you can guess, and only one is right, so the probability of guessing right is 1/12.
That depends on what the range of the guess is and whether you mean three consecutive times. Example : for guessing a number between 1 and 10 inclusive (10 numbers) the odds are 1 in 10 for each guess, or 0.1. To guess it correctly twice in a row the odds would be 0.1 x 0.1 or (0.1)², which is .01, or one in a hundred. To guess it correctly three times in a row, the odds would be 0.1 x 0.1 x 0.1 or (0.1)³, which is .001 or one in a thousand. It is the range or numbers raised to the power of the number of required correct consecutive guesses. Another example: guess a number between one and fifty inclusive twice in a row. The formula would be : odds=1/(50)², which is 1/2500 or one in 2500.
The correct spelling of the noun is "paraphernalia" (odds and ends).
there is a 50/50 chance that the test are wrong.
There is not one. In statistics, if the number of possibilities and desired outcomes does not decrease, the probability stays the same with each trial. Meaning that each guess would be the same probability as the previous guess. Now if your looking at guessing something that can have a limited number of correct guesses, like whether I'm typing this answer on a Windows, Mac or Linux machine, each guess eliminates a possible answer. So the odds would be better if you guessed Mac and then I said you were wrong and you guessed again.
Assuming he received the correct treatment, odds are HIGH he is cured. But, how can he not know he had it and not know he had treatment?