One percocet will definitely not lead to overdose. It depends how much of the methamphetamine was used to gauge whether or not you will overdose.
Yes. Tylenol also known by the names acetaminophen or paracetamol and often abbreviated as apap is contained in Percocet. 1 Percocet tablet contains anywhere from 325 mg to 650mg of acetaminophen so care should be used when taking it in order to avoid an unintentional overdose of acetaminophen.
4 tylenol 3 equal 1 percocet
There are no limits to the possibilities.
Overdose - 2013 was released on: USA: 1 October 2013 USA: 1 October 2013 (Kingdomwood Film Festival)
Mike Hammer - 1956 Overdose of Lead 1-10 was released on: USA: 21 March 1958
550 x (-1) and an infinite number of other possibilities
Amphetamines stay in the system for 1-3 days, methamphetamines stay in the system for 3-6 days.
1. To remove incorrect possibilities in order to reach a correct solution or possibility.
3 possibilities 1 - you die 2 - you end up in a hospital very sick and then get committed to a facility 3 - you pass out. latter on you wake up. no one knows unless you open your mouth. don't try it. you have a 2/3 possibility of a bad result!
Oxycontin and Percocet are both oxycodone not morphine or hydromorphone.
Given:Length (L) = 10Characters: 0, 1, therefore Count (n) = 25 consecutive zeros or 5consecutiveonesI'll try to map out some logic for you. I'm sorry this took so many edits for me to get the correct answer. These problems can some times be a little tricky, and I just kept tripping up on the logic.:First, calculate the maximum amount of possibilities, without any constants.This step is optional, however it gives you a check on your final answer.Length = 10n = 2Therefore, the maximum amount of possibilities without any constants is 2^10 = 1084. If you get a number higher than 1084, which in one of my edits I did, than your answer is obviously incorrect.Case 1: Fiveconsecutivezeros[0][0][0][0][0][?][?][?][?][?] ==> 2^5 possibilities (2 x 2 x 2 x 2 x 2)[1][0][0][0][0][0][?][?][?][?] ==> 2^4 possibilities[?][1][0][0][0][0][0][?][?][?] ==> 2^4 possibilities[?][?][1][0][0][0][0][0][?][?] ==> 2^4 possibilities[?][?][?][1][0][0][0][0][0][?] ==> 2^4 possibilities[?][?][?][?][1][0][0][0][0][0] ==> 2^4 possibilities (1 possibility duplicated from case 2)Case 2:[1][1][1][1][1][?][?][?][?][?] ==> 2^5 possibilities (2 x 2 x 2 x 2 x 2)[0][1][1][1][1][1][?][?][?][?] ==> 2^4 possibilities[?][0][1][1][1][1][1][?][?][?] ==> 2^4 possibilities[?][?][0][1][1][1][1][1][?][?] ==> 2^4 possibilities[?][?][?][0][1][1][1][1][1][?] ==> 2^4 possibilities[?][?][?][?][0][1][1][1][1][1] ==> 2^4 possibilities (1 possibility duplicated from case 1)Special Cases (don't count these, they are counted twice in previous cases)[0][0][0][0][0][1][1][1][1][1] ==> 1 possibility (counted in case 1)[1][1][1][1][1][0][0][0][0][0] ==> 1 possibility (counted in case 2)We need to subtract 2 from the final answer to account for this.As you can see, the number of possibilities for each case are:2^5 + 5(2^4) = 112There are two cases, you can multiply that by 2 to get your answer.2(2^5 + 4(2^4)) = 2(112) = 224 possibilitiesSubtract the special cases:224 possibilities - 2 possibilities = 222 possibilitiesThe answer to the question is:There are 222 unique ten bit strings that contain five consecutive zeros or five consecutive ones.
1 pill of adderal will not result in an overdose, but you should have a perscription. No one has ever over dosed (died) from weed. If one hit is too much then try less or don't smoke.