Mg has +2, S has +6, O has -2
Explanation: O (oxygen) generally has -2 oxidation state ( exceptions exist like peroxides)
Mg(magnesium) is an alkaline earth metal which has fixed oxidation state of +2 in its compunds.
S(sulphur) shows variable oxidation state..
To get its oxidation state: we use the fact the total sum of oxidation state of all atoms in a compound is zero. For ions this sum is equal to the charge on the ion.
Let oxidation state of S be x.
Then we have: +2 (for Mg) + (-2)*4(for 4 O atoms) + x = 0
Which gives x=+6.
+2 for Mg
-2 for each O
+6 for S
+2 for Mg
+6 for S
-2 for each O
+1 for H
Each O is -2, for a total of -8. Mg is +2. Therefore, S is +6 (because the whole thing must add up to 0).
The oxidation number for the atoms in magnesium sulfite are: Mg+2, S+4, O-2. The sum of the oxidation numbers in a neutral compound is 0.
MgSO4
O.S. of Mg = +2
O.S. of S = +6
O.S. of O = -2
The oxidation state of an individual sulfur atom in MgSO4 is +6.
It has plus six state.Mg has plus two and oxygen -2.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number of Al is +III and S is -II.
Oxidation no of sulphur is +2.
The oxidation state of an individual sulfur atom in MgSO4 is +6.
It has plus six state.Mg has plus two and oxygen -2.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number of Al is +III and S is -II.
Oxidation no of sulphur is +2.
S has an oxidation number of -2. Al is +3.
oxidation number of oxygen is -2 s = +5/2
This compound is sodium thiosulphate. S represents +6 oxidation number.
S = +2 oxidation state cl = -1 oxidation state
This is the thiosulfate ion. Sulfur shows +6 oxidation number.
The oxidation number of S in S8 is ZERO!
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