CO is a harmful gas.C shows +2 in CO and it shows +4 in CO2.
The symbol equation for the reduction of iron ore with carbon monoxide is Fe2O3 + 3CO ----> 2Fe + 3CO2. Iron is extracted from its oxide ores, primarily hematite, by reduction with carbon monoxide in a blast furnace.
Assuming you mean what is the oxidation number of each atom in the compound C3H8O? Oxidation rules state the the sum of all oxidation numbers in a neutral molecule equals 0. 1. O = -2 2. H = +1 3. C = -2 These numbers are derived from... (-2) + (+1 x 8) + (-2 x 3) = 0
H is +1, F is -1, therefore C is -2 ( the sum of the oxidation numbers of the elemnts in an electronically neutral atom is defined as zero)
Oxidation number of C is +3. Oxidation number of O is -2.
Oxidation numbers up to +7 is possible. For example: +7 for Cl in HClO4 or Cl2O7. +6 for S in SO3 or H2SO4 +5 for N in HNO3 or N2O5 +4 for C in CO2
C + O2 --> CO 3CO + Fe2O3 --> 2Fe + 3CO2
The symbol equation for the reduction of iron ore with carbon monoxide is Fe2O3 + 3CO ----> 2Fe + 3CO2. Iron is extracted from its oxide ores, primarily hematite, by reduction with carbon monoxide in a blast furnace.
-1 for each iodine, +4 for C
Assuming you mean what is the oxidation number of each atom in the compound C3H8O? Oxidation rules state the the sum of all oxidation numbers in a neutral molecule equals 0. 1. O = -2 2. H = +1 3. C = -2 These numbers are derived from... (-2) + (+1 x 8) + (-2 x 3) = 0
H is +1, F is -1, therefore C is -2 ( the sum of the oxidation numbers of the elemnts in an electronically neutral atom is defined as zero)
Oxidation number of C is +3. Oxidation number of O is -2.
Oxidation numbers up to +7 is possible. For example: +7 for Cl in HClO4 or Cl2O7. +6 for S in SO3 or H2SO4 +5 for N in HNO3 or N2O5 +4 for C in CO2
Ethanal = C2H4O O.S of O = -2 O.S. of H = +1 O.S. of C = -1
Oxidation number is 4, formula C3O2O=C=C=C=O
Co = +2 oxidation C = +4 oxidation O = -2 oxidation
It might look like this: Fe2O3 + 3CO => 2Fe + 3CO2 The oxide of iron plus carbon monoxide yields iron and carbon dioxide. The key is that the carbon monoxide must "strip" all the oxygen from the iron oxide. Add as many CO molecules to the equation as needed to take up the oxygen from iron. We added the 3 in front of the CO to get 3CO. That results in the 3CO2 in the end product. We just need to add a 2 in front of the Fe to get 2Fe to balance the equation.
+4 oxidation state