x5 - 2x4 - 24x3 = 0
x3(x2 - 2x - 24) = 0
x3(x2 + 4x - 6x - 24) = 0
x3(x - 6)(x + 4) = 0
x = {-4, 0, 6}
Yes. In general, two matrices of the same size can be added.
6y(2x4)=
If you mean '2x4' as in 2 times 4- 2x4= 8 3x3= 9 4x2= 8 8-9-8=-19 if you want to divide by x -b/c x doesn't have a set amount- it would be: -19/x
(2 x 4) squared8 squared8x864
2*(4*4*4)=128
2x4 does not equal 7, it equals 8. 2x4=8 is a correct statement.
the answer is 0!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I was the one who made it an unanwser question?
The rule in /mathemtics, when no brackets are given, is DO THE MULTIPLCATUION/DIVISION before addition /subtraction. You calculator is programmed this way. Hence -3 -2 X 4 = -3 - 8 = -11 Notice I have made the mukltiplication be forde the subtraction. However, if the sum is wrtitten as (-3-2)x 4 , then you do the brackets first . ( -5) x 4 = -20 It is definitely NOT -6 x 4
I think you mean this as an answer, not a question. An expression does not have an equals sign (e.g 2x4). An equation does have an equals sign (e.g 2x4=8).
2x4
1x8 2x4 16x.5 32x.25
Find all rational roots of: x5 - 2x4 + 11x3 - 22x2 - 12x + 24 = 0
if you mean 2n=8, then N=4, which translate to 2x4=8
2x4-56 2x4=8 8-56= -48)
Yes.
because think of 2x4=8 and 8 divided by 4 or 2 equals 4 or2 OK :)
The length is 16 and the width is 4. 2x16 plus 2x4 equals 40.