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Passions - 1999 9-176 was released on:

USA: 17 June 2008

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281-645-9176?

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Substance weighing 124g heated in boiling water to 100 deg C placed in a calorimeter w300.0g of water temp of water increased from 20C to26C Heat of substance transferred to water?

Okay looney, number one, stop cheating on your chemistry test. Number two, try using proper grammar in the future. It allows you to be less confusing and get a better answer. Since the heat capacity of one gram of water is 4.2 Joulle per gram, we can take 6 (26C - 20C = heat raised = 6) and multiply that by 4.2 J (the amount of energy put into each gram of water) and 300.0 (how many grams there are) so: 4.2 J x 6*C x 300.0 g let's whip out the calculator = 7560 J*Cg We're not done yet. We need to compensate for how many grams are in the substance, and how much the temperature has decreased. Since we know that 100*C is our constant, and that the substance has decreased to 26*C (assumably) we need to figure out how many degrees we lost in total. 100*C - 26*C = 74*C 74*C x 124 g = 9176 *Cg Now we divide the two so we can get an answer in Joules. 7560 J*Cg / 9176 *Cg = 0.833 J because everything else eliminates. Try that one and see what you get.