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solvent=ethanol solute=sucrose because sucrose is added to ethanol.
25 % sucrose
4.32
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
Ethanol is the solvent and sucrose is the solute.
solvent=ethanol solute=sucrose because sucrose is added to ethanol.
solvent=ethanol solute=sucrose because sucrose is added to ethanol.
This is a homogeneous solution.
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
25 % sucrose
4.32
If it is made by weight, .5 % sucrose solution will be 5 g of sucrose (sugar) dissolved per 100 g of solvent (e.g. water)
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
That could be determined fairly easily by taste. Sucrose has a sweet flavor which ethanol does not.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.
You've got it in reverse. When sucrose dissolves in water, sucrose is the solute, and water is the solvent. In order to dissolve, sucrose molecules have to be more attracted to water molecules than they are to other sucrose molecules. If the attraction of sucrose to sucrose was greater than the attraction of sucrose to water, then there would be no reason for the solid sucrose to turn into the aqueous sucrose solution. Sucrose molecules would simply remain firmly attached to each other if that were the case.