The spectator ions are Ag+ and (NO3)-.
Sodium and nitrate.
BaNO3 + MnSO4 --> MnNO3 + BaSO4 (Manganes(II) nitrate and barium sulfate) (double replacement reaction)
A white precipitate reaction
Barium Sulphate
vanadium (III) sulfate + barium iodide =>
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
The spectator ions are Ag+ and (NO3)-.
Ammonium sulfate reacts with barium nitrate to form ammonium nitrate and barium sulfate. (NH4)2SO4 + Ba(NO3)2 ==> 2NH4NO3 + BaSO4 It is a double replacement reaction. that is the correct answer
BaNO3 + MnSO4 --> MnNO3 + BaSO4 (Manganes(II) nitrate and barium sulfate) (double replacement reaction)
A white precipitate reaction
If the sodium sulfate and barium nitrate are both in solution in water, a precipitate of barium sulfate will be formed, because this salt is much less soluble in water than barium nitrate, sodium sulfate, or sodium nitrate.
Barium Sulphate
Barium nitrate + Iron = [No reaction] Ba(NO3)2 + Fe = [No reaction]
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
Ba(NO3)2 + H2SO4 --> BaSO4 + 2HNO3 A barium sulfate salt and more acid; nitric acid.
vanadium (III) sulfate + barium iodide =>
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
Yes.