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What are the products of a reaction between potassium iodide and barium sulfide?
The reaction between potassium iodide (KI) and barium sulfide (BaS) will produce potassium sulfide (K2S) and barium iodide (BaI2) as products. This reaction involves a double displacement reaction, where the cations and anions of the two compounds switch partners.
Formula for barium iodide?
BaI2 is the chemical formula for Barium Iodide.
What is the balanced equation of barium acetate and potassium iodide?
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
What happens when you mix potassium iodide with barium nitrate?
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
What Copper sulfate solution and potassium iodide?
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
Is there a precipitation reaction between potassium sulfate and strontium iodide?
Yes, a precipitation reaction occurs when potassium sulfate and strontium iodide are mixed. Potassium sulfate and strontium iodide react to form strontium sulfate, which is insoluble in water, leading to its precipitation as a solid.
What happens in single replacement when bromine reacts with barium iodide?
In a single replacement reaction between bromine and barium iodide, bromine will replace iodine in barium iodide, forming barium bromide and iodine gas. The balanced chemical equation for this reaction is 2Br₂ + BaI₂ → 2BaBr + I₂.
What is the anion of barium iodide?
The anion of barium iodide is iodide (I-).
What are the products of a reaction between potassium iodide and barium sulfide?
The reaction between potassium iodide (KI) and barium sulfide (BaS) will produce potassium sulfide (K2S) and barium iodide (BaI2) as products. This reaction involves a double displacement reaction, where the cations and anions of the two compounds switch partners.
Formula for barium iodide?
BaI2 is the chemical formula for Barium Iodide.
Will BaCl and KI form a reaction?
Yes, when Barium chloride (BaCl2) and Potassium iodide (KI) are mixed, a reaction will occur. BaCl2 and KI will undergo a double displacement reaction to form Barium iodide (BaI2) and Potassium chloride (KCl).
What is the balanced equation of barium acetate and potassium iodide?
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
What happens when you mix potassium iodide with barium nitrate?
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
What Copper sulfate solution and potassium iodide?
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
What is the chemical equation for potassium bromide plus barium iodide changes to potassium iodide plus barium bromide?
2 KBr + BaI2 ----> 2 KI + BaBr2
Is barium iodide soluble?
Yes, barium iodide is soluble in water. It will dissolve and dissociate into barium ions (Ba2+) and iodide ions (I-) in solution.
What is the Reaction of iron sulphate with potassium iodide?
When iron sulfate reacts with potassium iodide, a double displacement reaction occurs where potassium sulfate and iron(II) iodide are formed. The balanced chemical equation for this reaction is FeSO4 + 2KI → FeI2 + K2SO4. This reaction is characterized by a color change from yellow (iron sulfate) to brown (iron(II) iodide).
