no reaction in aq solution, but if both powder used iodine will be generated with so2 releasing.......i am trying to work out the mechanism
When iron reacts with potassium iodide, it forms potassium iodide. The reaction can be written as 2Fe + 2KI → 2K + 2FeI. Potassium iodide is a salt and is commonly used as a nutritional supplement.
The color of aqueous iron(II) sulfate is typically pale green. When potassium iodide is added, it reacts with iron(II) ions to form a dark brown precipitate of iron(II) iodide.
When ferric chloride (FeCl3) is added to a solution of potassium iodide (KI), it reacts to form iron(III) iodide (FeI3) and potassium chloride (KCl). The iron(III) iodide produced is a brownish-red color, indicating the presence of the Fe3+ ion. This reaction can be represented by the following chemical equation: 2FeCl3 + 6KI -> 2FeI3 + 6KCl
When potassium dichromate reacts with iron (II) sulfate in an acidic solution, a redox reaction occurs. The dichromate ions are reduced to chromium (III) ions, while iron (II) ions are oxidized to iron (III) ions. The overall reaction is 6Fe2+ + Cr2O72- + 14H+ -> 6Fe3+ + 2Cr3+ + 7H2O.
Lithium carbonate + Iron(II) iodide ----> Lithium iodide + Iron(II) carbonateLi2CO3 + FeI2 ----> 2 LiI + FeCO3
When iron reacts with potassium iodide, it forms potassium iodide. The reaction can be written as 2Fe + 2KI → 2K + 2FeI. Potassium iodide is a salt and is commonly used as a nutritional supplement.
The color of aqueous iron(II) sulfate is typically pale green. When potassium iodide is added, it reacts with iron(II) ions to form a dark brown precipitate of iron(II) iodide.
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
Iron(Fe) + Copper Sulphate(CuSO4) → Iron Sulphate(Fe2SO4) + Copper(Cu)[Displacement Reaction]
When ferric chloride (FeCl3) is added to a solution of potassium iodide (KI), it reacts to form iron(III) iodide (FeI3) and potassium chloride (KCl). The iron(III) iodide produced is a brownish-red color, indicating the presence of the Fe3+ ion. This reaction can be represented by the following chemical equation: 2FeCl3 + 6KI -> 2FeI3 + 6KCl
In a displacement reaction between iron and copper sulphate, iron, being more reactive than copper, will displace copper from copper sulphate solution. The chemical equation for this reaction is: Fe + CuSO4 -> FeSO4 + Cu. This reaction results in the formation of iron sulphate and copper metal.
Iron sulphate can be both a reactant and a product, depending on the chemical reaction. It can react to form different compounds or be produced from the reaction of iron and sulphuric acid.
no reaction between ammonium sulphate and iron sulphate
yes there is
When iron reacts with potassium chloride, a single displacement reaction occurs. The iron displaces potassium in the compound, forming iron chloride and potassium metal. The balanced chemical equation for this reaction is 2Fe + 2KCl -> 2K + 2FeCl3.
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
Any reaction occur.