In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
Chlorine, a more reactive halogen would displace iodide in its hallide solution. Potassium chloride would be formed.
iodine and chloride ions
no
Potassium chloride and Iodine
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
Leroy Egerton Westman has written: 'Equilibrium constant for ferric chloride, potassium iodide, ferrous chloride and iodine'
Chlorine, a more reactive halogen would displace iodide in its hallide solution. Potassium chloride would be formed.
iodine and chloride ions
no
Worded Equation; Potassium Iodide + Calcium Chloride ------> Potassium Chloride + Calcium Iodide Chemical Equation; KI (l) + CaCl (l) -----> KCl (aq) + Ca(I)2 (aq) Note Answer is only correct if proper states are applied and used.
Potassium chloride and Iodine
The chemical equation is:2 KI + Cl2 = 2 KCl + I2
Sodium chloride (NaCl) is table salt. Additives may include potassium chloride and potassium iodide.
A precipitate of Lead iodide and Potassium nitrate are formed
somehow. the potassium iodide act as a acidifying agent,
The solution of potassium iodide (if it is not extremely diluted) is more dense.