0
What else can I help you with?
Is barium iodide soluble?
Yes, barium iodide is soluble in water. It will dissolve and dissociate into barium ions (Ba2+) and iodide ions (I-) in solution.
What is the anion of Barium Chloride?
The anion of barium chloride is chloride (Cl-). Barium chloride is an ionic compound composed of the cation barium (Ba2+) and the anion chloride.
What is barium iodide symbol?
Formula: PbI2
Barium carbonate anion formula?
The forumula for Barium Carbonate is BaCO3
Is barium iodide a solid?
barium nitrate is aqueous because all nitrates are soluble.
Formula for barium iodide?
BaI2 is the chemical formula for Barium Iodide.
Is barium iodide soluble?
Yes, barium iodide is soluble in water. It will dissolve and dissociate into barium ions (Ba2+) and iodide ions (I-) in solution.
What is the name of compound Bal2?
Compound Bal2 is also known as Barium iodide.
What is the anion of Barium Chloride?
The anion of barium chloride is chloride (Cl-). Barium chloride is an ionic compound composed of the cation barium (Ba2+) and the anion chloride.
What is the name for the compound BaI2?
The compound BaI2 is called barium iodide. It is composed of a barium cation (Ba2+) and two iodide anions (I-).
What is barium iodide symbol?
Formula: PbI2
Is barium hydroxide a cation or an anion?
Barium hydroxide is not a cation or an anion. It is a compound. It is made of barium ions and hydroxide ions.
Barium carbonate anion formula?
The forumula for Barium Carbonate is BaCO3
What is the chemical formula for barium ions and iodide ions?
The chemical formula for barium ions is Ba2+ and for iodide ions is I-.
Is barium iodide an acid or a base?
Barium iodide is neither an acid nor a base. It is a salt composed of a metal (barium) and a nonmetal (iodine).
How many barium ions are there in 250 mL of a barium iodide solution that has an iodide ion concentration of 0.125 M?
The number of barium ions is 0,188.10e23.
What is the reaction for vanadium III sulfate barium iodide?
The reaction between vanadium (III) sulfate (V2(SO4)3) and barium iodide (BaI2) would form barium sulfate (BaSO4) and vanadium (III) iodide (V2I3). This reaction is a double displacement reaction.
