Sodium iodide is a salt.
Barium iodide is BaI2 . So there's two times more I- than Ba2+[I-] = 2*0.193 = 0.386 mol/L I- ions
A barium ion has a charge of 2+ and an iodide ion has a charge of 1-, therefore, two iodide ions are needed to balance the barium ion. Ba2+ + 2I- --> BaI2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
Bromine replaces the iodide to form a Bromide.BaI2 + Br2 ----> BaBr2 + I2
BaI2 is the chemical formula for Barium Iodide.
Barium Sulfate (BaSO4) is neither an acid nor a base it is a salt
It is a base
Iodide
Yes. Barium Iodide is soluble in water.
Neutral
Barium hydroxide, Ba(OH)2, is a base.
hydrogen iodide (HI) is one of the strongest acids
vanadium (III) sulfate + barium iodide =>
Compound Bal2 is also known as Barium iodide.
Sodium iodide is a salt.
ammonium iodide = NH4INH4+ is the conjugate acid of the weak base NH3. It is acidic.I- is the anion of the strong acid, HI. It is neutral.Therefore the solution is acidic with a pH < 7.