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Volume: 3xy = 30 and so xy = 10

Area: 2(3x)+2(xy)+2(3y) = 59 => x = 6.5-y

So: (6.5-y)y = 10 => 6.5y-y2-10 = 0

Solving the quadratic equation: y = 2.5 or y = 4

Values by substitution are: when x = 2.5 cm then y = 4 cm

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Q: What are the values of x and y of a cuboid whose dimensions are 3 cm by x cm by y cm having a volume of 30 cubic cm and a surface area of 59 square cm showing work?
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