international interprited intern
Quicksort in any programming language is an algorithm for sorting data sequences. It is typically implemented as follows (example demonstrates a quicksort of an array of type int). Note that a half-open range, [begin:end), includes the one-past-the-end of the range and is the conventional means of defining a range of contiguous array values. When begin==end, the range is deemed empty. // forward declarations void qsort (int* unsigned); // this is the function you will actually invoke void qsort_rec (int*, int*); // recursive function int* partition (int*, int*); // utility functions... int* select_pivot (int*, int*); void swap (int*, int*); int count (int*, int*); // sort a data sequence of length size void qsort (int* data, unsigned size) { qsort_rec (data, data + size); } // recursively sort the half-open range [begin:end) void qsort_rec (int* begin, int* end) { if (count (begin, end) < 2) return; // end point of recursion int* pivot = partition (begin, end); qsort_rec (begin, pivot); qsort_rec (++pivot, end); } // divide the half-open range [begin:end) into two around a pivot value int* partition (int* begin, int* end) { if (count (begin, end) < 2) return begin; int* pivot = select_pivot (begin, end); swap (begin, pivot); --end; while (begin != end) { while (*(begin) <= *pivot && begin != end) ++begin; while (*pivot < *(end) && begin != end) --end; if (begin!=end) swap (begin, end); } assert (begin==end); // sanity check! swap (pivot, begin); return begin; } // select the median of three from a half-open range [begin:end) int* select_pivot (int* begin, int* end) { int* mid = begin + (count (begin, end) / 2); if (*end<*begin) swap (begin, end); if (*mid<*begin) swap (begin, mid); if (*end<*mid) swap (mid, end); return end; } // swap the values referred to by p and q void swap (int* p, int* q) { if (!p !q) return; // sanity check! int t = *p; *p = *q; *q = t; } // count the elements in the half-closed range [begin:end) int count (int* begin, int* end) { int cnt = 0; int add; if (begin>end) { // swap pointers if the range is reversed int* t = begin; begin = end; end = t; add = -1; // count will be negative } else { add = 1; // count will be positive } while (begin++!=end) cnt+=add; return cnt; }
Are you sure that these words (normal int and regular int) actually mean something?
Several words begin with the letters soph. However, there are no words that end with the letters soph.
Lots of words begin with quart such asQuarter
int n1; int n2; int n3; int n4; int n5; int n6; int n7; int n8; int n9; int n10; int n11; int n12; int n13; int n14; int n15; int n16; int n17; int n18; int n19; int n20; int n21; int n22; int n23; int n24; int n25; int n26; int n27; int n28; int n29; int n30;
Many words begin with the letter t. However, no words in the English language begin with the letters tl.
Here is the Code: #include<stdio.h> #include<ctype.h> enum {OPT_C=4, OPT_W=2, OPT_L=1}; int print(const char *fname, int opt, int chars, int words, int lines) { if(opt&OPT_L) printf("% 8d", lines); if(opt&OPT_W) printf("% 8d", words); if(opt&OPT_C) printf("% 8d", chars); if(fname[0]!= '-') printf(" %s", fname); putchar('\n'); return 0; } int wc(const char *fname, int opt, int *tot_chars, int *tot_words, int *tot_lines) { int ch; int chars=0; int words=0; int lines=0; int sp=1; FILE *fp; if(fname[0]!= '-') fp=fopen(fname, "r"); else fp=stdin; if(!fp) return -1; while((ch=getc(fp))!= EOF) { ++chars; if(isspace(ch)) sp=1; else if(sp) P ++words; sp=0; } if(ch== '\n') ++lines; } print(fname, opt, chars, words, lines); if(fname[0]!= '-') fclose(fp); *tot_chars+=chars; *tot_words+=words; *tot_lines+=lines; return 0; } int main(int argc, char *argv[]) { int chars=0; int words=0; int lines=0; int nfiles=0; int opt=0; int n; while((++argv[0] && argv[0][0]= '-') { n=1; while(argv[0][n]) { switch(argv[0][n++]){ case 'c': opt|=OPT_C; break; case 'w': opt|=OPT_W; break; case 'l': opt|=OPT_L; break; default: fprintf(stderr, "Unknown option %c\n", argv[0][n-1]); fprintf(stderr, "Usage: wc [-cwl] [<filename>*]\n); return -1; } } } if(!opt) opt=OPT_L|OPT_W|OPT_C; while(argv[0]) { ++nfiles; if(wc(*argv, opt, &chars, &words, &lines); perror(*argv); return 1; } } if(nfiles==0) wc("-", opt, &chars, &words, &lines); else if(nfiles>1) print("total", opt, chars, words, lines); return 0; } Answer while (argv[0]) -- what does it do? try this: for (i=1; i<argc; ++i) { ...process argv[i]... }
There are no complimenting words that begin with X.
There are more than 100,000 words that begin with the letter A.
A few words that begin with letter A are:aardvarkaboutactoraddAesopafteraggravateaheadaimajarakimboalgebraamountandapplyaquiferarrangeaskattributeaugmentavariceawakeaxayeazure
There are no English Scrabble words that begin with QUL.
There are no words in the English language that begin with the letters ez.