CO2- carbon dioxide. CO- carbon monoxide. CH4- methane.
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
CH4(g) + H20(g) <----> CO(g) + 3H2(g)
3 CH4 + 5 O2 ----> 2 CO + CO2 + 6H2OThe reaction generates quantities of carbon monoxide along with carbon dioxide and water.
flames produces light enery co,co2,and other compounds
Carbon and hydrogen. For this reason, CO and CO2 are not considered organic compound, whereas CH4 is.Carbon and Oxygen I think..
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
CH4(g) + H20(g) <----> CO(g) + 3H2(g)
bcoz in inorganic compounds with "carbon", "hydrogen" is also required which is absent in CO2 , CO, CO3 carbide etc.
3 CH4 + 5 O2 ----> 2 CO + CO2 + 6H2OThe reaction generates quantities of carbon monoxide along with carbon dioxide and water.
Balanced equation. CH4 + 2O2 -> CO2 + 2H2O one to one, but set-up anyway and limiting reacting known 2.0 moles CH4 (1 mole CO2/1 mole CH4) = 2.0 moles CO2 produced ( by the way, those numbers are subscripts, not superscripts )
2.0%CO2, 5.5%CO, 32%CH4, 51.9%H2 , 0.3O2 and 4.8%N2
flames produces light enery co,co2,and other compounds
carbon dioxide (CO2), water (H2O), and carbonmonoxide(CO) are only a few compounds containing oxygen.
the answer to this very question is.....Organic...
Exhaust, which is made up of different carbon compounds such as co2, co, ect.
Chemistry involving compounds that have carbon in them that are more complex than CO2, CO or like CaCO3
Carbon and hydrogen. For this reason, CO and CO2 are not considered organic compound, whereas CH4 is.Carbon and Oxygen I think..