Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The balanced chemical equation for this reaction is: CH4 + 2O2 -> CO2 + 2H2O. This equation shows that one methane molecule reacts with two oxygen molecules to produce one carbon dioxide molecule and two water molecules.
A combustion reaction is a reaction that burns. The equation that represents a combustion reaction is CH4 + 2O2 reacts to yield CO2 + 2H2O.
The balanced equation for the conversion of methane (CH4) to carbon dioxide (CO2) is: CH4 + 2O2 -> CO2 + 2H2O To convert methane to carbon dioxide, you would need to combust methane in the presence of oxygen, which will produce carbon dioxide and water as products.
Since there is no limit on the amount of oxygen described in the question, you can assume that all the methane reacts with the oxygen. The reaction is CH4 + 2O2 --> CO2 + 2H2O The question asks for the amount of CO2 that is formed in grams so you need to know the soichiometric ratio between methane and carbon dioxide which in this case is 1:1. After that, it's just dimensional analysis. 12g CH4 X (1 mol CH4/16.032g) X (1mol CO2/1 mol CH4) X (44g CO2/1 mol CO2) = 32.93g of CO2 produced.
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The balanced chemical equation for this reaction is: CH4 + 2O2 -> CO2 + 2H2O. This equation shows that one methane molecule reacts with two oxygen molecules to produce one carbon dioxide molecule and two water molecules.
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
A combustion reaction is a reaction that burns. The equation that represents a combustion reaction is CH4 + 2O2 reacts to yield CO2 + 2H2O.
The balanced equation for the conversion of methane (CH4) to carbon dioxide (CO2) is: CH4 + 2O2 -> CO2 + 2H2O To convert methane to carbon dioxide, you would need to combust methane in the presence of oxygen, which will produce carbon dioxide and water as products.
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
Since there is no limit on the amount of oxygen described in the question, you can assume that all the methane reacts with the oxygen. The reaction is CH4 + 2O2 --> CO2 + 2H2O The question asks for the amount of CO2 that is formed in grams so you need to know the soichiometric ratio between methane and carbon dioxide which in this case is 1:1. After that, it's just dimensional analysis. 12g CH4 X (1 mol CH4/16.032g) X (1mol CO2/1 mol CH4) X (44g CO2/1 mol CO2) = 32.93g of CO2 produced.
If you're talking about a chemical equation for a situation where you have an environment containing only methane and propane, there can be no balanced equation because with no oxygen, neither gas will burn.
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O