The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
Methane + Bromine --> Bromomethane + Hydrogen bromide
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
CH4
CH4 + Cl2 → CH3Cl + HCl - monohlor metan CH3Cl + Cl2 → CHCl2 + HCl - dihlor metan CHCl2 + Cl2 → CHCl3 + HCl - trihlor metan CHCl3 + Cl2 → CCl4 + HCl - tetrahlor metan
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
Al4C3 +12H2O = 4Al(OH)3 + 3CH4
Methane + Bromine --> Bromomethane + Hydrogen bromide
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
CH3COOH = CH4 + CO2 or CH3COO + H
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
Yes. Except that the word is equals, not eqauls.
A combustion reaction.
The reaction is: CH4 + 4Cl2---------------------CCl4 + 4HCl
It is a combusion.It generates water and CO2