Al4C3 +12H2O = 4Al(OH)3 + 3CH4
this equation is wrong, it should be Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 +CaSO4 and when balanced, it is Al2(SO4)3 + 3Ca(OH)2 --> 2Al(OH)3 +3CaSO4
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
Aluminum Hydroxide
Aluminium Hydroxide or in other terms Al(OH)3
You need to know the separate concentrations of the different substances in order to find the volume necessary
this equation is wrong, it should be Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 +CaSO4 and when balanced, it is Al2(SO4)3 + 3Ca(OH)2 --> 2Al(OH)3 +3CaSO4
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
Aluminum Hydroxide
Al(OH)3
Aluminium hydroxide - Al(OH)3
Aluminium Hydroxide or in other terms Al(OH)3
Al(OH)3 Indicates that there are three OH groups per Al metal
Al(OH)3 is a base (Aluminum hyroxide)
You need to know the separate concentrations of the different substances in order to find the volume necessary
The molar mass of aluminium hyroxide is approximately 78 g/mol.
That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3
Aluminum forms a +3 ion, and hydroxide's formula is OH-, so the formula for aluminum hydroxide would be: Al(OH)3