Combustion. Methane is CH4 and it can undergo combustion with oxygen (O2) to form CO2 + H2O.
CH4 + 2O2 ===> CO2 + 2H2O ... balanced equation
methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
The reactants are methane CH4 and oxygen O2 and the products are carbon dioxide CO2 and water H2O. CH4 + 2 O2 --> CO2 + 2 H2O
The balanced equation for the combustion of natural gas (methane, CH4) is: CH4 + 2 O2 -> CO2 + 2 H2O This equation shows that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
methane + oxygen -> carbon dioxide + water 2 Methane molecules plus 4 Oxygen molecules gives 2 molecules of Carbon dioxide plus 4 Water molecules.
Methane plus oxygen produces carbon dioxide and water.
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
The reactants are methane CH4 and oxygen O2 and the products are carbon dioxide CO2 and water H2O. CH4 + 2 O2 --> CO2 + 2 H2O
The balanced equation for the combustion of natural gas (methane, CH4) is: CH4 + 2 O2 -> CO2 + 2 H2O This equation shows that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
yes
The chemical equation for the reaction between carbon dioxide and oxygen to form methane is not possible as it involves a reduction process, which is not spontaneous under normal conditions. Methane is usually produced through other processes, such as the reaction between hydrogen and carbon dioxide known as Sabatier reaction.
Oxygen would be represented as O2 in the formula equation for the reaction of methane and oxygen to yield carbon dioxide and water. This is because oxygen exists as a diatomic molecule in its natural state and needs to be balanced accordingly in the equation.
Photosynthesis does not directly involve methane. It is a process by which plants, algae, and some bacteria convert carbon dioxide and water into glucose using sunlight. Methane is a different compound produced by microorganisms in anaerobic conditions.
methane + oxygen ---> water + carbon dioxide. Don't put an equal sign ! ( = )