Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363.
If that is the case solve the following equation:
(n-1) + (n) + (n+1) = -363 to give you the middle integer.
There is no set of three consecutive integers for 106.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
There are no three consecutive odd integers who's sum equals 13.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
The integers are -19, -18 and -17.
There is no set of three consecutive integers for 187.
The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.
There is no set of three consecutive integers for 106.
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
9240 is the product of the three consecutive integers 20, 21, and 22.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
There are no three consecutive odd integers who's sum equals 13.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
The three integers are 187, 188 and 189.