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There are two types of gametes Which are the names of these two types?
Eggs and sperm
What is the chemical formula of PG PR?
There is no chemical compound known to me as PG PR.
What are the two types of plate divergences?
Two types of divergent plates are Eurasian and Nazca
What are the types of reproduction?
The types are two - sexual and asexual.
What are the two types of season?
The two types of seasoning are the natural/air seosoning and the kiln seasoning
What is the difference between the multiplication rule for independent versus dependent events?
Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.
If you roll one die with 6 sides what is the probability that you will roll a 3 or a 4?
The answer is 1/3. There are six possible outcomes (1 to 6) of which two (3 or 4) are favourable so the probability is 2/6 or 1/3. In general, if A and B are two events, then Pr (A or B) = Pr(A) + Pr(B0 - Pr(A and B) [the last bit is because you are double counting those events] Here Pr(A) = Pr(3) = 1/6, Pr(B) = Pr(4) = 1/6 and Pr(A and B) = Pr(3 and 4 - simultaneously) = 0 So Pr(3 or 4) = 1/6 + 1/6 + 0 = 1/3
What is the probability of obtaining exactly three heads in four flips of a coin given that at least two are heads?
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
What is the probability of rolling two fair value dice getting two different numbers?
Pr(Two different numbers) = 1 - Pr(Two same) = 1 - 1/6 = 5/6 = 83.3%
What is the probability of getting a sum of 7 and 11 when two number cubes are rolled?
Pr(7) = 1/36 Pr(11) = 2/36 = 1/18
What are the two forms of phytochrome and how are they switched?
Phytochromes exist in two interconvertible forms PR because it absorbs red (R; 660 nm) light PFR because it absorbs far red (FR; 730 nm) light These are the relationships: Absorption of red light by PR converts it into PFR Absorption of far red light by PFR converts it into PR. In the dark, PFR spontaneously converts back to PR.
Which includes immediate deliberate and unassisted ways to execute the military PR option?
PR methods include the deliberate and unassisted ways of executing the military PR option.
What is the describing of the complementary event and find its probability?
Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).
What is the probability when two people alternately are picking first from a class with 12 girls and 13 boys and then from a class with 10 boys and 11 girls that the first will pick two girls first?
The fact that the two people are picking alternately first from one class and then from the second means that the first picker always has first selection from whoever is remaining in each class; thus for the first picker: pr(1st girl) = 12/(12+13) = 12/25 Pr(2nd girl) = 11/(11+10) = 11/21 → Pr(two girls picked) = pr(1st girl) × pr(2nd girl) = 12/25×11/21 = 44/175
What is the probability of getting at most one tail when two coins are tossed together?
pr(at most one T) = 1 - pr(not two tails) = 1 - 1/2*1/2 = 1 - 1/4 = 3/4
What does PR mean in the medical field?
pr
Two events A and B with probability 0.5 and 0.7 respectively have joint probability of 0.4 The probability that neither A nor B happens is?
Let me denote -A as the event that A does not happen. So we want Pr[-(A and B)] Now, the event that neither A nor B occurs is the opposite of either A occurring, or B occurring or both occurring. So Pr[-(A and B)] = 1 - Pr(A or B)= 1 - [Pr(A) + Pr(B) - Pr(A and B)] (since A+B is double counted)= 1 - (0.5 + 0.7 - 0.4)= 1 - 0.8= 0.2
