what can be inferred about the voltage across the bulb
The voltage across a battery in a parallel circuit is equal to the voltage across each bulb because Kirchoff's Voltage Law (KVL) states that the signed sum of the voltages going around a series circuit adds up to zero. Each section of the parallel circuit, i.e. the battery and one bulb, constitutes a series circuit. By KVL, the voltage across the battery must be equal and opposite to the voltage across the bulb. Another way of thinking about this is to consider that the conductors joining the battery and bulbs effectively have zero ohms resistance. By Ohm's law, this means the voltage across the conductor is zero, which means the voltage across the bulb must be equal to the voltage across the battery and, of course, the same applies for all of the bulbs.
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
A bulb does not light up if there is no voltage available across the bulb, or if the bulb is burned out.
In parallel, each bulb will have full voltage applied across them. However, in series, the voltage across each bulb won't be the same as supply voltage. Thereby, bulbs connected in parallel will glow brighter.
if the resistance of bulb A is 2x that of B then there will be twice as much voltage across it (ratio 2:1 ). both voltages shall equal the system voltage assuming they are in series and there are no other components in the circuit if the bulbs are in parallel the voltage across them will be equal and that of the system
the voltage across it is reduced, the voltage is shared with other bulbs
Power is current times voltage, so a current of 0.5 amperes and a voltage of 220v across a bulb will yield a power of 110 watts.
Exactly...you answered your own question. Each DC bulb will drop voltage according to its resistance and the amount of current it draws.
The brightness of a standard bulb is directly proportional to the amount of voltage drop across the bulb itself. Thus, to increase the brightness :-Pass more current across the bulb by reducing the resistance of the circuitIncrease the voltage across the bulb, or the circuit. Change the supply.
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
By taking the voltage across the bulb and multiply by the current flow.
because i dont know