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An object seems to weigh less when submerged in water because the buoyancy of the water is greater than that of air, causing a force to be applied to the object, reducing the apparent net force that is required to support the object.

However, gravity is gravity, and the object still weighs the same. Its just that there is an additional force acting on the object in opposition to the force of gravity. If you were to weigh a volume of water, and then weigh it again with an object in it, you would discover that the total weight did, in fact, increase by the weight of the object.

Note that this is all independent of the object's mass. Mass and weight are two different things, and they should not be confused. The object's mass also does not change just because it is submerged in water. To illustrate this last point, an object in outer space does not weigh anything, because the net force of gravity is zero, but the object still has mass, and it requires the same force it always did in order to accelerate it at a certain rate.

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Q: What causes an object to weigh less when submerged in water?
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How much more does an object weigh after it has been submerged out of water?

Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.


When an object is submerged will it weigh less or have less mass?

Objects under water seem to weigh less but they have the same mass as they would out of water.


How do you find density of irregular shape?

Measure the displacement of water when the object is submerged in water. This gives the volume ; then weigh the object and divide the weight by the volume to get the density.


How do you find density of an irregular shape?

Measure the displacement of water when the object is submerged in water. This gives the volume ; then weigh the object and divide the weight by the volume to get the density.


What is the underwater weight of an object that sinks to the bottom of a body of water and is completely submerged?

You will find that such an object will weigh its weight on land minus the weight of the water it displaceswhen submerged. It doesn't seem possible, but it is true. This kind of result is called 'counterintuitive'.


Does the fact that an object has been submerged in water make it weigh more when you take it out because it has soaked up water?

It depends what the object is. If it can soak up water then yes. If it is made of plastic then no.


Why do things seem to weigh less in water?

An object has to push the water out of the way (or in other words, displace water) in order to become submerged; the weight of that displaced water creates an opposing force called buoyancy, which pushes the object upward, out of the water.


Does a floating object weigh more when underwater?

Statistically it weighs the same, but it feels less when it is submerged underwater.


If the mass of an object is weigh and the object is dropped in cylinder containing water but the object is not fully under water will this affect the density?

The density of what? But regardless the answer to that: Density is mass per volume. Mass is not influenced by the upward force of the fluid in which the object is submerged. The weight, on the other hand, is. Weight is a force, and mass is an amount of matter.


The set up of apparatus of Archimedes principle?

If you want to test the principle that the bouyant force on a submerged object is equal to the weight of the water it displaces, here is a procedure. Get a balance scale and weigh the object by hanging the object from a string attached to the scale pan (rather then just placing it on the pan). Next, place the hanging object in a graduated cylinder with a known amount of water. The water level in the graduated cylinder will rise when the object is submerged. The amount the water rises will give you the volume of water displaced and you can calculate the weight of that amount of water knowing the density of water. Next, readjust your balance scale to get the object's weight while submerged. You should find the objects weight has decreased by an amount equal to the weight of the displaced water. Meaning the water is exerting an upward "bouyant" force by this amount.


Does water weigh more when an object is placed in it?

no


Does an object weigh more in water or in air?

air