0
What combinations can make 17 with the numbers123456789101112 but only use a number once?
Wiki User
∙ 12y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
How many 5 numbers combinations can you make from numbers 1 through 35 and you can use multiple combinations but still use each number only once?
35
How manydifferent combinations can be made if second number is 2?
The whole point of combinations is that the order of the number (or items) does not matter. Once you specify what the second number is, you are no longer looking at combinations.
How many 6 numbers combinations can you make from 1 2 3 4 5 6 and you can use multiple combinations but still use each number only once?
720
How many 3 numbers combinations can you make from 1 3 7 using each number once?
137, 173, 317, 371, 713, 731 Six combinations can be made.
How many different combinations are possible is a coin is tossed once and a number cube is tossed twice?
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
How many 7 numbers combinations can you make from 1 2 3 4 5 6 7 and you can use multiple combinations but still use each number only once?
Not sure what "multiple combinations means.There is only one 7-number combination and that is 1234567 or 1357642 or any one of the other permutations.
How many 4 digit combinations using 0-9 if each number may be used more than once?
10,000 combinations.
How many 4 digit combinations can be made from the numbers 0 to 9?
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
How many 6 number combinations when each digit can be used more tan once?
about 12
How many different combinations are possible if a coin is tossed twice and a number cube is tossed once?
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
How many 5 number combinations are in 47?
Assuming a number can appear only once, there are 47C5 = 47*46*45*44*43/(5*4*3*2*1) = 1,533,939 combinations.
How many 4 number combinations using digits 1357 one and only once?
There is only one combination. The order of the digits in combinations makes no difference. They are considered as being different if they are permutations, not combinations.
