These temperatures are 0 0C and 100 0C.
At 0°C and 1 ATM, water exists in a state of equilibrium between its solid and liquid forms, known as the freezing point. In this state, ice and liquid water can coexist, with the molecules in the solid phase arranged in a crystalline structure while those in the liquid phase are more disordered and move freely. This point represents a key characteristic of water, highlighting its unique properties, such as its ability to remain in both states at the same temperature and pressure.
Water at 0°C and above 1 ATM pressure is in its liquid state. At this temperature, it is at the freezing point, but since the pressure is above 1 ATM, it does not freeze and remains liquid. This is due to the fact that water can exist as a liquid between 0°C and 100°C under normal atmospheric pressure. Thus, at 0°C and higher pressure, it will not transition to ice, but rather stay in its liquid form.
32 degrees Fahrenheit, or 0 degrees Celsius, is the melting point of water at 1 atm.
At 0 ATM the boiling point is extremely low. For example at 0.0000034 ATM, the boiling point is -67.78 Celsius. In an ideal vacuum it would be even lower than this but I don't know if it would be 0K or not. Referenced from the following resources: http://www.jbind.com/pdf/Cross-Reference-of-Boiling-Temps.pdf http://www.convertunits.com/from/psia/to/atmosphere+[standard]
Over 1 oC water is a liquid.
At the melting point (Explanation) if you look at the phase diagram and look at the point where the water is 0 degrees C and 1 atm, they meet right on the line. This is the line that shows the melting point of this substance. Therefore, since the point is on the line, water at 0 degrees C and 1 atm is at the melting point.
water changes from a gas to a solid to a liquid
The freezing point of water at 1 ATM (standard atmospheric pressure) is 0 degrees Celsius or 32 degrees Fahrenheit. At this temperature, water changes from a liquid to a solid state.
The melting point of ultrapure water is 0 0C at 1 atm.
These temperatures are 0 0C and 100 0C.
At 0°C and 1 ATM, water exists in a state of equilibrium between its solid and liquid forms, known as the freezing point. In this state, ice and liquid water can coexist, with the molecules in the solid phase arranged in a crystalline structure while those in the liquid phase are more disordered and move freely. This point represents a key characteristic of water, highlighting its unique properties, such as its ability to remain in both states at the same temperature and pressure.
Water at 0°C and above 1 ATM pressure is in its liquid state. At this temperature, it is at the freezing point, but since the pressure is above 1 ATM, it does not freeze and remains liquid. This is due to the fact that water can exist as a liquid between 0°C and 100°C under normal atmospheric pressure. Thus, at 0°C and higher pressure, it will not transition to ice, but rather stay in its liquid form.
32 degrees Fahrenheit, or 0 degrees Celsius, is the melting point of water at 1 atm.
At 0 ATM the boiling point is extremely low. For example at 0.0000034 ATM, the boiling point is -67.78 Celsius. In an ideal vacuum it would be even lower than this but I don't know if it would be 0K or not. Referenced from the following resources: http://www.jbind.com/pdf/Cross-Reference-of-Boiling-Temps.pdf http://www.convertunits.com/from/psia/to/atmosphere+[standard]
Yes, water is liquid at 1 atm and 25 C. Temperature is the other important variable, though. Because, at 1 atm and 0 C, water becomes a solid. At 1 atm and 100 C, water becomes a gas. On the surface of the planet, we have an atmospheric pressure of 1 atm. So, when you see water at room temp, it's a liquid.
There is 1 ATM at sea level, so 0 (zero) feet of water. If you need to calculate other pressures or depths: http://www.grc.nasa.gov/WWW/K-12/WindTunnel/Activities/fluid_pressure.html