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What are the boiling point and the freezing points of water in Fahrenheit and Celsius?
At STP ie (1 Atm or 101.325 kPa, 760mm Hg) The boiling point of pure water is 212 °F or 100 °C The freezing point of pure water is 32 °F or 0 °C
Using the phase diagram for H2O, which of the following correctly describes water at 0°C and 1 atm?
At the melting point (Explanation) if you look at the phase diagram and look at the point where the water is 0 degrees C and 1 atm, they meet right on the line. This is the line that shows the melting point of this substance. Therefore, since the point is on the line, water at 0 degrees C and 1 atm is at the melting point.
What would the final freezing point of water be if 3 mole of sugar were added to 1 kg of water?
The CHANGE in freezing point can be determined from ∆T = imK where ∆T is the change in freezing point, i is van't Hoff factor (1 for sugar, a non electrolyte), m is molality (moles solute/kg solvent), and K is the freezing point constant for water (1.86). Thus ∆T = (1)(3)(1.86) = 5.58ºC. So, the FINAL freezing point will be -5.58ºC
At 1 ATM of pressure water boils at 100 C if the sample was placed under 2.5 ATM of pressure what would be the temperature?
At 2.5 ATM of pressure, water would boil at a higher temperature than 100°C. The boiling point of water increases as pressure increases. For every increase of 1 ATM in pressure, the boiling point of water increases by 10°C. Therefore, at 2.5 ATM, water would boil at approximately 125°C.
How much Would the freezing point of water decrease of sugar were added to 1 kg of water?
The freezing point of water decreases by about 1.86 degrees Celsius for each mole of solute (such as sugar) dissolved in 1 kg of water. So, the freezing point would decrease by 1.86 degrees Celsius for every mole of sugar added.
What is the freezing point and boiling point of water when the pressure of the water is 1 atm?
These temperatures are 0 0C and 100 0C.
What is the pressure (in ATM) at the normal boiling point of water?
1 atm
What is the pressure in ATM at the normal boiling point of water?
At the standard atmospheric pressure of 101325 Pa water boils exact at 100 degrees Celsius.
What are the boiling point and the freezing points of water in Fahrenheit and Celsius?
At STP ie (1 Atm or 101.325 kPa, 760mm Hg) The boiling point of pure water is 212 °F or 100 °C The freezing point of pure water is 32 °F or 0 °C
What phase is water in at 1atm pressure and -5c?
At 1 atm pressure and -5°C, water is in the solid phase, commonly known as ice. This temperature is below the freezing point of water (0°C at 1 atm), leading to the formation of solid ice. Therefore, at these conditions, water would not exist as a liquid.
Using the phase diagram for H2O, which of the following correctly describes water at 0°C and 1 atm?
At the melting point (Explanation) if you look at the phase diagram and look at the point where the water is 0 degrees C and 1 atm, they meet right on the line. This is the line that shows the melting point of this substance. Therefore, since the point is on the line, water at 0 degrees C and 1 atm is at the melting point.
What is the melting point of pure matter distilled water?
The melting point of ultrapure water is 0 0C at 1 atm.
What described water at 100 Celsius and 1 ATM pressure?
Water at 100°C and 1 atm pressure is in its liquid state, commonly referred to as boiling water. At this temperature and pressure, water reaches its boiling point and begins to vaporize into steam.
What would be the final freezing point of water be if 3 mol of sugar were added to 1 kg of water?
-5.58 C
What is the freezing point of water at 16404 feet?
The freezing point of water decreases by about 1°F for every 500 feet increase in altitude. At 16,404 feet, the freezing point of water would be around 30°F.
What is water at 0 c and above 1 ATM pressure?
Water at 0°C and above 1 ATM pressure is in its liquid state. At this temperature, it is at the freezing point, but since the pressure is above 1 ATM, it does not freeze and remains liquid. This is due to the fact that water can exist as a liquid between 0°C and 100°C under normal atmospheric pressure. Thus, at 0°C and higher pressure, it will not transition to ice, but rather stay in its liquid form.
What would the final freezing point of water be if 3 mole of sugar were added to 1 kg of water?
The CHANGE in freezing point can be determined from ∆T = imK where ∆T is the change in freezing point, i is van't Hoff factor (1 for sugar, a non electrolyte), m is molality (moles solute/kg solvent), and K is the freezing point constant for water (1.86). Thus ∆T = (1)(3)(1.86) = 5.58ºC. So, the FINAL freezing point will be -5.58ºC
