0.4166666
No. The heat from the larger bulb will damage the socket, and is a fire hazard.
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
Less than 0.02 watt/hours. Running your 100w bulb for an hour uses 100 watt/hours. The inrush current during the cold resistance of the bulb lasts for only a millisecond before the bulb is hot. This is insignificant on your electric bill even if you sat and flicked the lightswitch for the whole month, and is a common misconception that someone who didn't know what they were talking about made up.
600w - the thicker filament has a lower resistance, which leads to a higher current and thus higher wattage
Power is measured in Watts, power (Watts) = E (volts) x I (current - amps) current is determined by the internal resistance (R) of the lightbulb, the lower the resistance the more current will flow. 120v x 0.5a = 60W 120V x 0.83a = 100W the 100W lightbulb will draw more current We also have Ohm's law: E(volts) = I (amps) x R (ohms) Household voltage stays the same at 120v we have for a 100w lamp: 120v = I x R R = 120v/0.83 amps R = 144.6 ohms for a 60w lamp: 120v = I x R R = 120v/0.5 amps R = 240 ohms The higher watt lamp has lower resistance.
No. The heat from the larger bulb will damage the socket, and is a fire hazard.
Assume the rating of 100W refers to operation on a supply of 117 volts.Power = (voltage) x (current)Current = (power) / (voltage) = 100/117 = 0.855 ampere (rounded)Power = (voltage)2 / (resistance)Resistance = (voltage)2 / (power) = (117)2 / 100 = 136.89 ohms
I also am wondering this...i hope someone answers this asap
9.8 sec
100/220 = .45A or 450 mA
80
The formula you are looking for is E = W/I.
what continent is 80s, 100w
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
Because when converting from one type of energy to another, something is always lost in the conversion. It's like pouring water between two buckets and always spilling a little. Let's say you're putting 100W of mechanical energy into turning the generator. This maybe gives you 80W of electric energy out from the generator. If you then put those 80W into a motor, you get maybe 60W of mechanical energy out of the motor. For each conversion you lose a bit more.
0.6kwh x 30 = 18kwh
Less than 0.02 watt/hours. Running your 100w bulb for an hour uses 100 watt/hours. The inrush current during the cold resistance of the bulb lasts for only a millisecond before the bulb is hot. This is insignificant on your electric bill even if you sat and flicked the lightswitch for the whole month, and is a common misconception that someone who didn't know what they were talking about made up.