I would say the most obvious is the length of the constituent waves.
The radiant energy increases as the frequency increase and the radiant energy decreases as the frequency decreases.
The wavelength decreases.
As wavelength decreases, frequency increases
When wavelength increases, frequency decreases.
Does the energy of a photon increase as the frequency decreases ? No.In fact it is just the opposite : energy increases as the frequency increases.The relation is very simple; it's just e=hv wheree is the energy of the photonh is Planck's constantv is the frequency of the radiation.( v should be the Greek letter nu, but this keyboard won't do it ! )
The wavelength is inversely proportional to its frequency. That is, as the frequency increases, the wavelength decreases and vice versa.
The radiant energy increases as the frequency increase and the radiant energy decreases as the frequency decreases.
The wavelength decreases.
The energy increases as the frequency increases.The frequency decreases as the wavelength increases.So, the energy decreases as the wavelength increases.
Using the relationship C = n lambda C - velocity of light, n-frequency of radiation and lambda- the wavelength. So as frequency increases definitely its wavelength decreases.
As wavelength decreases, frequency increases
As frequency increases the energy of a wave also increases.
As wavelength increases the frequency decreases.
In Electromagnetic radiation when the wavelength increases the energy transmitted by the wave decreases. E=hf where h is a constant and f is the frequency.
Wavelength.
The period decreases.
When wavelength increases, frequency decreases.