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Two billiard balls of equal mass undergo a perfectly elastic head collision. What will be their speeds after the collision.?
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
Factors that affect gravity between objects?
The force of gravity is F=G*m1*m2/r^2 G is the universal gravitation constant 6.67*10^-11 m^3kg^-1s^-2 m1, m2 are the masses of the two objects, r is the separation. The force on m1 acts in the direction of m2, and the force on m2 acts in the direction of m1.
Which law states The greater the mass the stronger the gravitational force The greater the distance the weaker the gravitational force?
Thats f (newtons) = (G * m1 * m2) / d2 where: G = newtons gravitational constant m1 = mass, object 1 m2 = mass, object 2 d = distance between
Two objects attract each other gravitationally with a force of 2.5x10-10 N when they are 25m apart Their total mass is 4.0kg find their individual masses?
Alright, so basically you're given: m1+m2=4.0kg, r=25m, Fg=2.5*10-10N We know that Fg=Gm1m2/r2 Using the fact that m1+m2=4.0kg, we know that m2=4.0kg-m1 So: Fg=Gm1(4.0kg-m1)/r2 =G(m1(4.0)-m12)/r2 So: (-G/r2)m12+(4G/r2)m1-Fg=0 Here we can use the quadratic formula to solve for m1 Once you have m1, just use m1+m2=4.0kg to find m2 I'll leave the actual number crunching to you. Hope this helps!
What is the formula for elastic collisions?
if we assume m1 (mass) and v1 (velocity) for first mass , m2 and v2 for second mass ,we have : m1 v1i + m2 v2i = m1 v1f + m2 v2f and 1/2 m1 v1i2 + 1/2 m2 v2i2 = 1/2 m1 v1f2 +1/2 m2 v2f2 i : initial f : final This is a simplified version: vf1= ((m1-m2)/(m1+m2))(v1i)+ (2m2/(mi+m2)vi2
Why are m3 and m2 higher than m1?
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
what does law of universal gravitational?
What is?? F = G m1 m2 / d2
What does the universal law of gravitation?
What is?? F = G m1 m2 / d2
What is the difference between M1 and M2?
What is the difference between M1 and M2?
What represents the correct relationship between the slopes of perpendicular lines?
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
If the m1 equals SA and m3 equals 23 what is the m?
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
What description of a scientific law that uses a math equation?
Law of Gravity: Fg = G(m1*m2)/r^2
What is the law of universal gravitatiion?
F = G M1M2/R2F and R are vectors.G, M1, M2 are scalars.
What does the slope on a force vs mass graph represent?
Let us suppose we are plotting y vs x and obtain a straight line. Then we pick a set of two coordinates, x1,y1 and x2,y2 The slope, M, is then given by the equation M (y2-y1)/(x2-x1) If we apply this to a force vs mass graph, we obtain the expression M (F2-F1)/(m2-m1),but F ma according to Newton's second law, where a is the acceleration, which leads to (m2a2-m1a1)/(m2-m1), but if a2 a1 a, as it will if the line is straight, then M a(m2-m1)/(m2-m1) a, so the slope, M, of your graph is acceleration.
Did Gravitational force Act in Vacuum If yes Which law explains it?
Gravitation acts everywhere including a vacuum, which is what outer space is. The attraction between two bodies of masses M1 and M2, a distance L apart, is proportional to (M1 x M2)/L2. This is Newton's Law Of Gravitation
What happens to the gravitational force when the distance between the 2 objects is trippled?
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
How do you write c code for ternary search?
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
