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The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about the force exerted on m2 due to the gravitational attraction between m1?
The force exerted on m2 due to the gravitational attraction with m1 is equal in magnitude but opposite in direction to the force exerted on m1. This is known as Newton's third law of motion - for every action, there is an equal and opposite reaction.
What is the gravitational formula for telling attraction?
The attraction between two objects is: G x m1 x m2 / distance squared where m1 and m2 are the two masses involved, and G is the gravitational constant - approximately 6.674 x 10 to the power -11, in SI units.
What is included in M2 but not in M1?
M2 includes M1 components (currency, demand deposits) along with savings accounts, time deposits, and non-institutional money market funds.
What are m2's and m1?
M2 and M1 are measures of the money supply. M1 includes physical money, such as paper currency and coins, as well as demand deposits and other liquid assets that can be quickly converted into cash. M2 includes all of M1 plus savings deposits, time deposits, and other non-cash assets that can be easily converted into cash.
Two billiard balls of equal mass undergo a perfectly elastic head collision. What will be their speeds after the collision.?
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
Why are m3 and m2 higher than m1?
because 3>2>1 ? Other than that, depends on what m1,m2 and m3 represent.
what does law of universal gravitational?
What is?? F = G m1 m2 / d2
What does the universal law of gravitation?
What is?? F = G m1 m2 / d2
What is the difference between M1 and M2?
What is the difference between M1 and M2?
What represents the correct relationship between the slopes of perpendicular lines?
If the slopes are m1 and m2 then m1*m2 = -1 or m2 = -1/m1.
If the m1 equals SA and m3 equals 23 what is the m?
if(m1>m2) f=m1; s=(m2>m3)?m1!m3 what its meaning of this?
What description of a scientific law that uses a math equation?
Law of Gravity: Fg = G(m1*m2)/r^2
The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about the force exerted on m2 due to the gravitational attraction between m1?
The force exerted on m2 due to the gravitational attraction with m1 is equal in magnitude but opposite in direction to the force exerted on m1. This is known as Newton's third law of motion - for every action, there is an equal and opposite reaction.
What is the law of universal gravitatiion?
F = G M1M2/R2F and R are vectors.G, M1, M2 are scalars.
What does the slope on a force vs mass graph represent?
Let us suppose we are plotting y vs x and obtain a straight line. Then we pick a set of two coordinates, x1,y1 and x2,y2 The slope, M, is then given by the equation M (y2-y1)/(x2-x1) If we apply this to a force vs mass graph, we obtain the expression M (F2-F1)/(m2-m1),but F ma according to Newton's second law, where a is the acceleration, which leads to (m2a2-m1a1)/(m2-m1), but if a2 a1 a, as it will if the line is straight, then M a(m2-m1)/(m2-m1) a, so the slope, M, of your graph is acceleration.
What happens to the gravitational force when the distance between the 2 objects is trippled?
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
How do you write c code for ternary search?
this procedure work for ternary search int tsearch(int *a,int i,int j,int k) { int m1,m2,len; len = j - i + 1 ; m1=i + (int)floor((float)(len))/3; m2=i + (int)ceil((float)(len))/3; if(k==a[m1]) { printf("\nno found at %d",m1); return m1; } else if(k==a[m2]) { printf("\nno found at %d",m2); return m2; } if(len!= 0) { if(k<a[m1]) return(tsearch(a,i,m1-1,k)); if(k>a[m2]) return(tsearch(a,m2+1,j,k)); } else return -1 ; }
