g denotes gaseous state.
gassy
g force
Helium weighs about 1/7 the weight of air. Air weighs about 1.2 g / L. Helium weighs about 0.17 g / L. 10mL of Helium would weigh about 0.0017 grams.
Which is more dense: water or helium? - Water is more dense, because water does not float like helium does. It is below air. That's why we have oceans and lakes and rivers.
Yes, a mole of hydrogen weighs 1 g, a mole of helium weighs 4 g. Still lighter than air, as a mole of air weighs about 30 g.
gaseous state
gassy
g force
Helium weighs about 1/7 the weight of air. Air weighs about 1.2 g / L. Helium weighs about 0.17 g / L. 10mL of Helium would weigh about 0.0017 grams.
Which is more dense: water or helium? - Water is more dense, because water does not float like helium does. It is below air. That's why we have oceans and lakes and rivers.
Yes, a mole of hydrogen weighs 1 g, a mole of helium weighs 4 g. Still lighter than air, as a mole of air weighs about 30 g.
Yes, all substances have density. Helium has a density of 0.1664 g/liter at 20°C and one atmosphere of pressure.
Helium(0.1786 g/L) is lighter than air(1.2 kg/m3) due to physical property density.Density of air is more than helium due to presence of many gase like oxygen carbon dioxide etc.
"Lift" is pretty much defined as the difference in weight of equal volumes of the lifting gas (helium or hot air) and the ambient air. As a comparison, a typical density of air is about 0.00018 g/cm3. At the same temperature and pressure, air would be about 0.00128 g/cm3. The difference is 0.00128 - 0.00018 = 0.0011 g/cm3. So 1 cm3 of helium can lift about 0.0011 g. Scaling that up, 1 m3 of helium could lift about 1.1 kg. To achieve equal buoyancy, the air would have to be heated to about 1850 °C. Normal operating temperatures for hot air balloons are closer to 120 °C. At this temperature, the air density is about 0.00090 g/cm3, so the lift would be about 0.00128-0.0090 = 0.00038 g/cm3 so by comparison, helium would be 0.0011/0.00038 = 2.9 times the lift of hot air.
Ok, this would be a problem of essentially displacement as the lift is caused by displacing "air".Ok, so one needs the densities of air and helium at some given temperature and pressure... "STP" is common, although one really would need to do it at the ambient temperature... or to do the final conversion using the simple formula PV=nRT.According to answers.yahoo.com, the densities of air and helium at STP are:Density of helium = 0.0001785 g/cm³Density of air = 0.001293 g/cm³,Ok, so your questions is how many cm³ of helium are needed to lift 1 gm.... let's try to make an equation.So, if we displace X cm³ of air with Helium we have:(X cm³)*(Density of Air g/cm³) - (X cm³)*(Density of Helium g/cm³) = (mass displaced in grams).Set the amount of mass being displaced to 1 gram, and putting in the densities we have:(X cm³)*(0.001293 g/cm³) - (X cm³)*(0.0001785 g/cm³) = 1 g(X cm³)*(0.001293 g/cm³ - 0.0001785 g/cm³) = 1 g(X cm³) = 1g/(0.001293 g/cm³ - 0.0001785 g/cm³)(X cm³) = 897 cm³You had asked in liters... with 1000 cm³/liter, the answer would be:0.897 liters of helium would displace 1 gram of oxygen without taking into account the weight of the container, or any pressure imposed by inflating container such as a rubber balloon.
4 g or helium is 1 mole. So, 0.12 g of helium is 0.03 mole
All the gases is too much ! But some examples are: Arsine AsH3 :3,29 g/dm3 Nitrogen dioxide NO2 :3,4 g/dm3 Carbon dioxide CO2 :1,87 g/dm3 Chlorine Cl :3,04 g/dm3 Fluorine F :1,59 g/dm3 The density of pure air is 1,2754 g/dm3 at standard pressure (100 kPa) and 0 0C. i dont care.