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What do you call a hydrate when it has lost its water moecules?
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∙ 11y ago
Anhydrous salt
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∙ 11y ago
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How do you identify the unknown substance as a percentage hydrate lab?
The formula for percent hydrate is calculated by taking the mass of the water lost and dividing by the mass of the hydrate.1. To calculate the water lost, subtract the value for the mass of the anhydrate (substance after it has been heated and dried [without water]) from the value for the mass of the hydrate (substance before it has been heated [with water]).Mass hydrate - mass anhydrate = water lostOR, another way to put itMass before heating - mass after heating = water lost2. Next, divide the mass of the water lost by the mass of the hydrate.Mass water lost- mass hydrateEx. A student was asked to identify an unknown hydrate by following the procedure described in this module. After heating and cooling, a 2.752g sample of this unknown weighed 1.941g. Students were given a list of possible compounds from which to identify their unknowns:LiNO3 * 3 H2OCa(NO3)2 * 4 H2OSr(NO3)2 * 4 H2OIn order to identify the unknown substance, the percent hydrate for the following compounds listed above needs to be calculated. This is done by first calculating the molar mass of each hydrate, then calculating the percent of water in each hydrate.Before proceeding, the amount of water lost needs to be calculated, followed by calculating the percent water in the unknown hydrate.Water lost: 2.752g hydrate - 1.941g anhydrate = 0.811gPercent water of hydrate: 29.47%0.811g2.751g x 100%1. Identify the molar mass of each hydrate.LiNO3 * 3 H2O (Lithium Nitrate Trihydrate)Molar Mass of LiNO3 (Lithium Nitrate): 68.9459gMolar Mass of 3 H2O (Water): 18.0152 * 3 OR 54.0456gMolar Mass of LiNO3 * 3 H2O = 122.9915g (add values above, not multiply!)Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate)Molar Mass of Ca(NO3)2 (Calcium Nitrate): 164.0878gMolar Mass of 4 H2O (Water): 18.0152 * 4 OR 72.0608gMolar Mass of Ca(NO3)2 * 4 H2O = 236.1486gSr(NO3)2 * 4 H2O (Strontium Nitrate Tetrahydrate)Molar Mass of Sr(NO3)2 (Calcium Nitrate): 211.6298gMolar Mass of 4 H2O (Water): 18.0152 * 4 OR 72.0608gMolar Mass of Sr(NO3)2 * 4 H2O = 283.6906g2. Calculate the percent water in each hydrate.Percent Water of Hydrate LiNO3 * 3 H2O (Lithium Nitrate Trihydrate) - 54.0456g122.9915g x 100 = 43.94%Percent Water of Hydrate Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate)- 72.0608g236.1486g x 100 = 30.52%Percent Water of Hydrate Sr(NO3)2 * 4 H2O (Strontium Nitrate Tetrahydrate)- 72.0608g283.6906g x 100 = 25.40%Due to the closest comparison in percentage values, the most likely compound is Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate). The values aren't exact matches probably because the water was not fully evaporated while being heated (leading calculations to indicate less water than there really was/is in substance). In other words, due to errors made on behalf of the experiment conductor by not completely heating the substance.Calculating Molar Mass of SubstancesElement A: Number Atoms Element A x Atomic Mass Element A = Mass AElement B: Number Atoms Element B x Atomic Mass Element B = Mass Betc.Add all of the mass values found above (Mass A + Mass B ...) and you have the value of molar mass. In the case above, to find the molar mass of the hydrates, simply add the molar mass of water (multiply by however many water molecules are in compound) and the molar mass of the other compound.
What three changes do a hydrate undergo upon heating?
Normally heating a hydrate drives of water (as vapor) thus the mass of the substance being heated will be less at the end of the heating.
What do you call a lion at the north pole?
Lost
How is transpiration used to replace lost water?
The water lost from the plant's leaves is replaced by the water coming in from the plant's roots.
What do you call a flamingo at the North Pole?
Lost.
Word to describe a compound that has lost the water in its crystals?
de-hydrate
How do you find the mass of water lost in hydrate?
By weighing the sample before and after heating to dehydration.
Which hydrates you more water or Gatorade?
When you are an athlete you lose chloride, sodium, and potassium due to sweating. Gatorade helps hydrate you and replace the electrolytes that are lost. Water does not replace your lost electrolytes. If you drink to much water it disturbs your electrolyte balance.
What is the different between a hydrated salt and anhydrous salt?
Hydrated salt-Salt with water of crystallization are called hydrated salt. Those water are bonded with dative bonds though.Anhydrous salt-Salt which have lost their water of crystallization are called anhydrous salt.
How do you identify the unknown substance as a percentage hydrate lab?
The formula for percent hydrate is calculated by taking the mass of the water lost and dividing by the mass of the hydrate.1. To calculate the water lost, subtract the value for the mass of the anhydrate (substance after it has been heated and dried [without water]) from the value for the mass of the hydrate (substance before it has been heated [with water]).Mass hydrate - mass anhydrate = water lostOR, another way to put itMass before heating - mass after heating = water lost2. Next, divide the mass of the water lost by the mass of the hydrate.Mass water lost- mass hydrateEx. A student was asked to identify an unknown hydrate by following the procedure described in this module. After heating and cooling, a 2.752g sample of this unknown weighed 1.941g. Students were given a list of possible compounds from which to identify their unknowns:LiNO3 * 3 H2OCa(NO3)2 * 4 H2OSr(NO3)2 * 4 H2OIn order to identify the unknown substance, the percent hydrate for the following compounds listed above needs to be calculated. This is done by first calculating the molar mass of each hydrate, then calculating the percent of water in each hydrate.Before proceeding, the amount of water lost needs to be calculated, followed by calculating the percent water in the unknown hydrate.Water lost: 2.752g hydrate - 1.941g anhydrate = 0.811gPercent water of hydrate: 29.47%0.811g2.751g x 100%1. Identify the molar mass of each hydrate.LiNO3 * 3 H2O (Lithium Nitrate Trihydrate)Molar Mass of LiNO3 (Lithium Nitrate): 68.9459gMolar Mass of 3 H2O (Water): 18.0152 * 3 OR 54.0456gMolar Mass of LiNO3 * 3 H2O = 122.9915g (add values above, not multiply!)Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate)Molar Mass of Ca(NO3)2 (Calcium Nitrate): 164.0878gMolar Mass of 4 H2O (Water): 18.0152 * 4 OR 72.0608gMolar Mass of Ca(NO3)2 * 4 H2O = 236.1486gSr(NO3)2 * 4 H2O (Strontium Nitrate Tetrahydrate)Molar Mass of Sr(NO3)2 (Calcium Nitrate): 211.6298gMolar Mass of 4 H2O (Water): 18.0152 * 4 OR 72.0608gMolar Mass of Sr(NO3)2 * 4 H2O = 283.6906g2. Calculate the percent water in each hydrate.Percent Water of Hydrate LiNO3 * 3 H2O (Lithium Nitrate Trihydrate) - 54.0456g122.9915g x 100 = 43.94%Percent Water of Hydrate Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate)- 72.0608g236.1486g x 100 = 30.52%Percent Water of Hydrate Sr(NO3)2 * 4 H2O (Strontium Nitrate Tetrahydrate)- 72.0608g283.6906g x 100 = 25.40%Due to the closest comparison in percentage values, the most likely compound is Ca(NO3)2 * 4 H2O (Calcium Nitrate Tetrahydrate). The values aren't exact matches probably because the water was not fully evaporated while being heated (leading calculations to indicate less water than there really was/is in substance). In other words, due to errors made on behalf of the experiment conductor by not completely heating the substance.Calculating Molar Mass of SubstancesElement A: Number Atoms Element A x Atomic Mass Element A = Mass AElement B: Number Atoms Element B x Atomic Mass Element B = Mass Betc.Add all of the mass values found above (Mass A + Mass B ...) and you have the value of molar mass. In the case above, to find the molar mass of the hydrates, simply add the molar mass of water (multiply by however many water molecules are in compound) and the molar mass of the other compound.
What is the formula for a hydrate?
CALCULATING MASS OF WATER LOST IN HYDRATETo calculate how much water was lost after a hydrate's been heated, subtract the mass of the anhydrate (after) from the mass of the hydrate (before).Mass Hydrate - Mass Anhydrate = Mass Water LostEXPERIMENTAL VALUE PERCENT WATER IN HYDRATETo calculate the experimental percent of water in a hydrate (using values gathered during the experiment), calculate how much water was lost (see "CALCULATING MASS OF WATER LOST" above). Do this by dividing the mass of the water lost (g) by the mass of the hydrate. Multiply the result by 100%.mass water lost- mass hydrate x 100%THEORETICAL VALUE PERCENT WATER IN HYDRATETo calculate the theoretical percent of water in a hydrate (using molar masses of substances rather than actual masses from experimental data), divide the molar mass of the water molecules by the molar mass of the hydrate; multiply the result by 100%.- Molar mass waterMolar mass hydrate x 100%Finding Molar Mass# atoms element A * atomic mass element A = Mass A# atoms element B * atomic mass element B = Mass B... etc.Add up all the mass values and you have the molar mass. Do this for both the anhydrate and water. For water's molar mass, you can also multiply 18.02 by the number of water molecules there are. This is a useful number to remember in order to save time test day and while doing homework practice problems too.To find the molar mass of the hydrate, add the molar mass values for water and the anhydrate.Molar Mass Water Molecules + Molar Mass Anhydrate = Molar Mass HydratePERCENT ERROR WATER IN HYDRATEIn order to determine the percent error of the water in a hydrate, subtract the experimental value (what you determined using values found via experimentation) from the theoretical value (what is determined using molar masses), then divide value by the theoretical value; multiply result by 100%.Theoretical Value - Experimental Value x 100%----------- Theoretical ValueEMPIRICAL FORMULA OF HYDRATES(looking for quantity of water molecules)In order to find how many water molecules there are within a hydration (finding the empirical formula for hydrate), follow the steps below according to what is given.1. Calculate percent water in substance.Divide the mass of water by the mass of the hydrate (before heating).- mass water*mass hydrate* see "CALCULATING MASS OF WATER LOST IN HYDRATE" above. Sometimes this number is already given. If it is, then proceed to the next step.2. Convert Mass to Moles.Divide the mass of substance by its molar mass.--------- Mass substance (g)Molar mass substance (g/mol) = molConversion Factormass substance (g) x 1 mol substance----------------- atomic mass substance (g) = mol substanceDo this for both the anhydrate and water.3. Find Mole Ratio; Multiply the number of moles until they are a whole number.Find the mole ratio by dividing the number of moles for each substance by the smallest number of moles within the compound.------- # mol anhydratesmallest # moles compound--------- # mol watersmallest # moles compoundAND/OR-- mol H2Omol hydrate = mol H2O per mol anhydrateMultiply or are within
What three changes do a hydrate undergo upon heating?
Normally heating a hydrate drives of water (as vapor) thus the mass of the substance being heated will be less at the end of the heating.
What do you call the ability of some animals to replace lost cells or lost body parts?
solution because its mixed with water
Why is water important to sportsmen?
to hydrate athletes need constant hydration due to water loss through sweating and to keep muscles well nurished.
What is the equation to use to find mass of x lost by hydrate?
Weight of hydrated substance - weight of same material after desiccation.
What do you call a lost animal?
Lost
What do you call a lion at the north pole?
Lost
