If you mean the straight line formula of: y = mx+b Then: 2x-3y-6 = 0 or y = 2/3 x -2 so m=2/3 and b=-2 If you mean that 2x-3y = -6 , then y = 2/3 x + 2 so m=2/3 and b= +2
If you mean: y = mx+b then m is the slope and b is the y intercept
If you mean: y = mx+b then m is the slope and b is the y intercept
finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!
If you mean: y = mx+b then m is the slope and b is the y intercept
(2,4) and (-4,8) y=mx+b 4=m(2)+b 4=2m+b b=y2-y1 /x2-x1 b = (8-4)/(-4-2) b=4/-2 b=-2 4=2m+-2 6=2m 3=m So your y=mx+b equation would be: y=3x+-2
The standard form of the equation is y = mx + b. m is the slope of the line. So the answer is 2. M = Slope B = Y - Intercept
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y=x+2 This equation is in the form of y=mx+b. Where m=the slope and b=y intercept. In this particular equation m=1 so the slope is 1 b=2 so the y intercept will be 2
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
If you mean y = mx+b then it is the equation formula of a straight line whereas m is the slope and b is the y intercept.
If you mean: y = mx+b then 'm' is the slope and 'b' is the y intercept for a straight line equation