it is a diatomic which makes it O2 and it has -2 charge
2C3H4O7 + O2 -> 6CO2 + 4H2O
The balanced reaction is this: 2CO + O2 --> 2CO2 This is correct... the correct way of balancing this is: CO+ 1/2O2 --> CO2 if you're using the above method to calculate enthalpy value then they will be different (and incorrect) compared to balancing it this way.
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.
2KClO2 + O2 = 2KClO3
2c + o2---2co
2Ca + 3O2 + 2C -> 2CaCO3
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4
c + c + 2c + c + c = 6c
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
4c+1-5+2c = 6c-4.
It is: 2c+8
Without any information about a or b or c, all that can be said is: a + b + 2c = a + b + 2c Not particularly illuminating!
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
(5a - 4b) + (2c - 3b - 6c) + a =5a - 4b + 2c - 3b - 6c + a =(5a + a) + (-4b - 3b) + (2c - 6c) =[ 6a - 7b - 4c ].
6c.
4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)