2 Lily White Boys (Green Grow The Rushes O) (song)
2 watts on a bulb
2 W on a B P stands for "2 wheels on a bicycle pump," which is a common riddle or puzzle.
Find the difference between the two teams' win and losses, divide by two. Example: Team A..........W-10 L-3 Team B..........W- 8 L-5 Team B is 2 games behind Team A Team A..........W-10 L-3 Team B..........W- 8 L-4 Team B is 1 1/2 games behind Team A
W- What U- u (you) B- been U- up 2- 2 (two)
it cannot be solved------------------------------------------------Actually, you can. Suppose, as an example, that the rectangle's area and perimeter are 6 and 10 respectively. Let therectangles length and width be represented by L and W respectively. ThenLW = 6 (a) and2 ( L + W ) = 10 (b)Let me rearrange (b) to obtain an expression for W: W = 5 - L.Now let me substitute this expression for W in (a): L ( 5 - L ) = 6.This is a quadratic equation that one can solve for L. Let me do it by factoring,L^2 - 5 L + 6 = 0 = ( L - 2 ) ( L - 3 )This implies that L=2 or L=3. With L=2, W=3; with L=3, W=2. Put simply the rectangle's length and width are 3 and 2 respectively.
B*w*l(2)
2 little dickie birds sitting on a wall
2 wheels of a bicycle Or...2 wings of a bird == ==
Cube/Rectangular Prism: 2(l*h) 2(l*w) 2(w*h) Square Pyramid: 4(1/2 (b*h))+(l*w) Just to name a few. Excuse any mistakes.
Let's assume that the rectangle has length 'l' and width 'w'. The formula for the area of a rectangle is A = l × w, and the formula for the perimeter (P) of a rectangle is P = 2(l + w). We're given that the area of the rectangle is 6cm², so: A = l × w = 6cm² We're also given that the perimeter of the rectangle is 14cm, so: P = 2(l + w) = 14cm We can use the second equation to solve for one of the variables in terms of the other: l + w = 7 l = 7 - w Substituting this into the equation for the area, we get: (7 - w) × w = 6 Expanding the left side of the equation, we get: 7w - w² = 6 Rearranging and factoring, we get: w² - 7w + 6 = 0 This equation can be factored as: (w - 1)(w - 6) = 0 So, w = 1 or w = 6. If w = 1, then l = 7 - w = 6, and the perimeter would be: P = 2(l + w) = 2(6 + 1) = 14 If w = 6, then l = 7 - w = 1, and the perimeter would still be: P = 2(l + w) = 2(1 + 6) = 14 Therefore, there are two possible solutions: a rectangle with dimensions 1cm × 6cm, and a rectangle with dimensions 6cm × 1cm.
It stands for Wireless local loop.
Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4 Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4