At open defence war fare
Water Freezes at 0 degrees celsius
0 Degrees Celsius at which Water Freezes
W = F x d W = Work F = Force d = Distance
Work is the scalr product of Force F and displacement D, W=F.D = fdcos(x) if the net force is zero W= 0.d= 0 or no work/
I dont know what you mean by 101 but d stands for da (slang) so like what DA fawk
32 degrees Fahrenheit at which water freezes
D. F. W van Lennep has written: 'The Alkestis'
The U.S. does not have any "F" mintmarks. Only P-D-S & W for any coins.
scientific work is F*D=W F=force D=distance W=work
32 Degrees Fahrenheit At Which Water Freezes
Work Done = Fs cos 0 OR- Work done by an expanding gas against a constant pressure would be w=F*d (Recall that F=PA; from P=F/A) W= (PA)d (volume = area*d) Therefore Work done = p (change in volume)
Written out f(w) = w^2 + 7w + 12 there is no particular answer since it depends on what w is equal to. normally this type of question is posited as "Solve for w with f(w) = 0?" or to change its form to (ax + b)(cx + d) if f(w) = w^2 + 7w + 12 and f(w) = 0 then 0 = w^2 + 7w + 12 simply look at the factors of 12 1 x 12 2 x 6 3 x 4 now consider (w + a)(w + b) = w^2 + aw + bw + ab = w^2 + (a+ b)w + ab since you know 3 x 4 = 12 , and 3 + 4 = 7 this give you 0 = (w + 3) (w + 4) or f(w) = (w + 3)(w + 4) solving for zero w = either -3 or -4 as (-3 + 3)(-3 + 4) = (0)(1) = 0 or (-4 + 3)(-4 + 4) = (-1)(0) = 0 so depending on what you are actually looking for the answer is w^2 + 7w +12 = (w + 3)(w + 4) or -3 and -4