+2
fe+3=..............* .9 =fe+2
Formula = Fe(ClO4)2Formula: Fe(ClO4)2
O3, with a molecular mass of 48 grams per mole
O3, what did you think? There is only one ozone.
Fe3O4 is a complex oxide (a crystaline solid containing more than one cation). In this case Fe exists as both the 2+ and 3+ cation. There are two 3+ ions and one 2+ ion for every four O2- ions. The charge balance is: 2x3+ + 2+ + 4x2- = 0
2 moles O3 (48 grams/1 mole O3) = 96 grams of ozone ==============
+2
fe+3=..............* .9 =fe+2
Formula = Fe(ClO4)2Formula: Fe(ClO4)2
Since Fe is a transition metal, the equation varies. If Fe has the oxidation state of +2: Fe + Cl2 -> FeCl2 If Fe has the oxidation state of +3: 2 Fe + 3 Cl2 -> 2 FeCl3
Its difficult to understand your question, I can make an assumption (although your stoichiometry is off). Are you asking about Iron Oxide compounds? Iron is a transition metal, abbreviated "Fe." It has two oxidative states, +2 and +3--often written as Fe (II) and Fe (III). If you have Fe(II) oxide, FeO, it would be called "ferrous oxide." If you have Fe(III) oxide, Fe2 O3, it would be called "ferric oxide." The other forms in your question aren't correct and I cannot answer them.
Fe is Iron, O is Oxygen, In this particular substance there are 3 of each. Making it Iron Oxide I believe. It comes in the form of a powder.
2 S2O32- + I2 --> S4O62- + 2 I-thiosulfate + iodine -> tetrathionate* + iodide* -O3=-=S-S-S-S=-=O3-
+2 for Fe, -2 for O
Fe2SO4 would be iron I sulfate. But no such compound exists. There are, however FeSO4 (Iron II sulfate) and Fe2(SO4)3 (iron III sulfate)
Cu 2 +