P1/t1=p2/t2
You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )
Volumes...If I remember correctly he proposed a theory called the Law of Combining Volumes: the ratio between the volumes of the reactant gases and the products can be expressed in simple whole numbers, i.e. similar to writing out a balanced chemical reaction.
P1 = 2T1 = 299T2 = 333V1 = 0.65V2 = 0.85P2t = P1 * T2 / T1 = 2.227 ATMP2v = P1 * V1 / V2 = 1.529 ATMP2 = P2t * P2v = 3.41 ATM
4.5181 atm P1/T1 = P2/T2 where T = temp in Kelvin
P1/t1=p2/t2
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1
Gay-Lussac's law. P1/T1 = P2/T2
T2 = P2 x T1 / P1
P1 = 3.85 atm; T1 = 25+273 = 298ºK; P2 = 18.0 atm; T2 = ?P1/T1 = P2/T2T2 = T1P2/P1 = (298)(18.0)/(3.85) = 1393ºK
Let P = Plant Let T = Time Let I = Insect P1 x T1 / I1 = P2 x T2 / I2 I2 =(P2)(T2)(I1) / (P1)(T1) P1 = 1 T1 = 1 I1 = 1 P2 = 25 T2 = 2 I2 = number of insects = 50
Formula:P1 P2---- = ----T1 T2P1= 740 mm HgP2= UnknownT1= 22°C= 295 KT2= -22°C= 251 K740 / 295 = P2 / 251P2= 630 mm Hg
At low pressures you can use the ideal gas equation: (P1*V1)/T1 = (P2*V2)/T2 At constant volume, the equation will be: P1/T1 = P2/T2 At higher pressures (appr. above 10 bar) the deviation to real gas becomes significant, hence the compression factor (Z) is introduced.
You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )
The pressure inside a CO2 extinguisher can vary depending on the temperature. Assuming it starts at room temperature, the pressure would increase as the cylinder is exposed to direct sunlight at 50°C. However, without further information, it is difficult to determine the exact pressure increase. It is important to note that CO2 extinguishers have pressure relief valves to prevent over-pressurization.