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What does G2 P1 T1 mean in GYN?

Updated: 12/22/2022
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Q: What does G2 P1 T1 mean in GYN?
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How can temperature be measured by determining the change in volume?

P1/t1=p2/t2


What is the formula for Gay-Lussac?

Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1


What is gay lussacs law formula?

Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1


What is the formula for gay lussacs law?

Gay-Lussac's Law states that the pressure of a sample of gas at constant volume, is directly proportional to its temperature in Kelvin. The P's represent pressure, while the T's represent temperature in Kelvin. P1 / T1 = constant After the change in pressure and temperature, P2 / T2 = constant Combine the two equations: P1 / T1 = P2 / T2 When any three of the four quantities in the equation are known, the fourth can be calculated. For example, we've known P1, T1 and P2, the T2 can be: T2 = P2 x T1 / P1


What is law in connection to pressure and temperature?

Gay-Lussac's law. P1/T1 = P2/T2


What is the formula of gay-lussac's law when the T2 is missing?

T2 = P2 x T1 / P1


An aerosol can has an internal pressure of 3.85 ATM at 25 C. What temperature is required to raise the pressure to 18.0 ATM?

P1 = 3.85 atm; T1 = 25+273 = 298ºK; P2 = 18.0 atm; T2 = ?P1/T1 = P2/T2T2 = T1P2/P1 = (298)(18.0)/(3.85) = 1393ºK


How do you write the addition problem to If one plant can capture one insect in one second how many insects could 25 plants trap in 2 seconds?

Let P = Plant Let T = Time Let I = Insect P1 x T1 / I1 = P2 x T2 / I2 I2 =(P2)(T2)(I1) / (P1)(T1) P1 = 1 T1 = 1 I1 = 1 P2 = 25 T2 = 2 I2 = number of insects = 50


A container of oxygen at 22 degrees Celsius and 740mm Hg is cooled to -22 degrees Celsius What is the new pressure of the gas?

Formula:P1 P2---- = ----T1 T2P1= 740 mm HgP2= UnknownT1= 22°C= 295 KT2= -22°C= 251 K740 / 295 = P2 / 251P2= 630 mm Hg


What is the relationship between density and temperature of CNG?

At low pressures you can use the ideal gas equation: (P1*V1)/T1 = (P2*V2)/T2 At constant volume, the equation will be: P1/T1 = P2/T2 At higher pressures (appr. above 10 bar) the deviation to real gas becomes significant, hence the compression factor (Z) is introduced.


What happens to the pressure of a gas when the volume of the container double in size?

You have for an Ideal Gas:PV = mRT/M( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = ConstantV2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )You have :( P1 / P2 ) = 1.00( T2 / T1 ) = 1.00( m2 / m1 ) = 2.00V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 )


How much the pressure inside CO2 extinguisher will be if the cylinder exposed to direct sunlight 50C degree?

The pressure inside a CO2 extinguisher can vary depending on the temperature. Assuming it starts at room temperature, the pressure would increase as the cylinder is exposed to direct sunlight at 50°C. However, without further information, it is difficult to determine the exact pressure increase. It is important to note that CO2 extinguishers have pressure relief valves to prevent over-pressurization.