Water and potassium sulfate
yes
Ch3och3
It will yield iron sulphate and water.
Kso4+h2o
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
yes
Ch3och3
Al2O3 + H2SO4 = Al2(SO4)3 + H2O
It will yield iron sulphate and water.
k2so4+hno2
Kso4+h2o
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.
koh + h2so4-khso4 +h2o
The equation is:2 KOH + H2SO4 = K2SO4 + 2 H2O
2KOH + H2SO4 = K2SO4 + 2H2O
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
H2so4 +2koh>k2so4+2h2o