Water and potassium sulfate
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
k2so4+hno2
First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
This chemical reaction represents a neutralization reaction, where an acid (H2SO4) reacts with a base (KOH) to form a salt (K2SO4) and water (H2O).
koh + h2so4-khso4 +h2o
The equation is:2 KOH + H2SO4 = K2SO4 + 2 H2O
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.