The total surface are of a rectangular prism s 2*(L*B + B*H + H*L) where L = length, B = breadth and H = height.
L=sqr((1/2 a+b+c) * (s-a) * (s-b) * (s-c))
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Given any number b > 2, let l = 2b/(b-2) then the rectangle with sides of l and b will have an area = l*b = 2b/(b-2) * b = 2b2/(b-2) and perimeter = 2*(l+b) = 2*[2b/(b-2) + b] =2*[2b/(b-2) + b(b-2)/(b-2)] = 2/(b-2)* [2b+b2-2b] = 2b2/(b-2) So that the area and perimeter have the same numeric value.
Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2
Use Pythagoras l^2 = a^2 + b^2 A = (7,9) & B= (3,12) NB 'A' & 'B' are NOT the same as 'a' & 'b' . Each is just a label, Hence l^2 = (7-3)^2 + (9 - 12)^2 l^2 = 4^2 + (-3)^2 l^2 = 16 + 9 l^2 = 25 l = sqrt(25) l = 5 The answer!!!!!
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Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.Perimeter = 2*(L + B)So 30 = 2*(9 + B)15 = 9 + B so that B = 6And therefore, Area = L*B = 9*6 = 54 sq metres.
.72 (mol/L)/s