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More frequency, and more energy.
The shorter the wavelength of a wave, the higher its energy.
The study of quantum effects on electrons and their interaction with other particles, especially photons. Usually it is considered as part of a larger context.
when the wavelength become smaller frequency becomes larger
Visible region is the shortest region in the electromagnetic spectrum. Please see the attached picture. It is the shortest defined region. However if you mean wavelength, the further you go on the UV side, the shorter the wavelength. If you are talking about frequence, frequency and wavelength are inversely proportional, so it would be furthest to the IR side. The question is not about the shorter wavelength or less frequency. It is about the region covered in the whole spectrum. So visible with VIBGYOR having wavelength starting from 350 nm to 750 nm will be the visible region where as other regions such as UV and IR would have a larger range.
More frequency, and more energy.
Yes. The wavelength of radiation is w=hc/Energy. Gamma energy is larger than infrared energy, thus has shorter wavelength.
I assume you are talking about electromagnetic radiation.If the wavelength is shorter, the frequency is larger. And the energy per photon is directly proportional to the frequency.
The shorter the wavelength of a wave, the higher its energy.
there are no slow moving photons, they move at speed of light.
Wave velocity in general = frequency x wavelength As the velocity of the wave remains constant then frequency and wavelength are inversely related So as the wavelength becomes shorter then frequency becomes larger or higher
Usually, no. The wavelength of visible light is usually measured in nanometers. Only larger forms of electromagnetic radiation, like radio waves, are measured in meters.
For electromagnetic waves:Speed(v)=frequency(f)*wavelength(lambda)ORwavelength(lambda)=speed(v)/frequency(f)Therefore, wavelength and frequency have an Inverse relationship this means that assuming speed remains constant if the wavelength increases (gets longer) the frequency will decrease.
The study of quantum effects on electrons and their interaction with other particles, especially photons. Usually it is considered as part of a larger context.
Radio telescopes are much larger than optical telescopes because of wavelength. Earth's atmosphere has two major "windows" where it is transparent to photons: 300 nm - 800 nm: optical wavelength window (approximate) 30 mm - 30 m: radio wavelength window (approximate) Even the shortest-wavelengths used by radio telescopes at around 30 mm are still thousands of times longer than the longest wavelengths used by optical telescopes. The wavelength has 2 effects on the size of a telescope: * The angular resolution (in order to distinguish 2 nearby stars, FWHM) depends on the wavelength/aperture ratio. Radio-frequency photons require a wider aperture to focus than visible-light-frequency photons, so radio telescopes *must* be larger to get a reasonable resolution. * A telescope typically requires the collecting area to be aligned within 1/10 of the wavelength it is designed for. Because it is almost impossible to get all the parts of a sufficiently large telescope aligned to within 80 nm, radio telescopes *can* be built much larger.
IF by "kc" you mean the outdated term kilocycles [a measurement of frequency, usually used in measuring electromagnetic radiation (radio)] then the larger (greater) the magnitude, the higher the frequency and the shorter the wavelength. This is basic physics... Your description indicates a poor mastery of technical English.
when the wavelength become smaller frequency becomes larger