indirect proportionality
A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).
In a displacement-time graph, the gradient represents velocity. In a velocity-time graph, the gradient represents acceleration.
Your acceleration vs. Time graph is the slope of your velocity vs. time graph
To create an acceleration-time graph from a velocity-time graph, you need to find the slope of the velocity-time graph at each point. The slope represents the acceleration at that specific instant. Plot these acceleration values against time to get the acceleration-time graph.
A constant acceleration on a velocity-time graph would appear as a straight line with a non-zero slope. The slope of the line represents the acceleration, with a steeper slope indicating a greater acceleration.
It looks like a line steadily getting higher and higher
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
The position vs time graph of an object shows its location at different times, while the velocity vs time graph shows how fast the object is moving at those times. The slope of the position vs time graph represents the velocity on the velocity vs time graph.
No, acceleration is the rate of change of velocity with respect to time. It is the derivative of the velocity function, not the slope of the velocity vs. time graph. The slope of the velocity vs. time graph represents the rate of change of velocity, not acceleration.
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
Two different distance-time graphs have matching velocity-time graphs when the slope of the distance-time graph represents the velocity in the velocity-time graph, as velocity is the derivative of distance with respect to time. This means that the steeper the distance-time graph, the greater the velocity on the velocity-time graph at that point.