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What does initial velocity squared plus 2 times acceleration times distance equal?
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How do you calculate the initial speed?
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
If a car goes in 6.8 seconds how do you figure out the acceleration?
Acceleration= distance / velocity squared
How is average velocity different from acceleration?
For a start, acceleration doesn't even have the same units as velocity: acceleration is a velocity divided by time, so while speed or velocity have units of [distance]/[time], acceleration has units of [distance]/[time squared]
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
Why do we measure acceleration in squared seconds as opposed to just seconds?
Speed, or velocity, is measured in distance per second; it is the rate of change of distance with time.Acceleration is the rate of change of velocity with time, or distance per second per second, which is distance per seconds squared,
How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
How do you calculate the initial speed?
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
Why the second is squared in acceleration?
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
If a car goes in 6.8 seconds how do you figure out the acceleration?
Acceleration= distance / velocity squared
How is average velocity different from acceleration?
For a start, acceleration doesn't even have the same units as velocity: acceleration is a velocity divided by time, so while speed or velocity have units of [distance]/[time], acceleration has units of [distance]/[time squared]
How do you calculate velocity final with distance and acceleration?
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
State in words how acceleration is calculated?
There are two methods, it depends on what variables you have: 1. Subtract the initial velocity from the final velocity and divide that whole term by the time (Vf- Vi)/t = a 2. Square both the initial velocity and the final velocity and subtract the squared inital velocity from the squared final velocity and that answer by two times the distance (Vf^2 - Vi^2)/2d = a
How do you calculate the height an object reaches using only time and acceleration g?
Assuming (a) an initial velocity of zero, and (b) constant acceleration, the formula becomes: distance = 0.5 at2 (distance = 1/2 times acceleration times time squared).
How do you find acceleration if only given a velocity?
If you have an initial and final velocity and time you can figure it out with this equation, Vf squared=Vi squared1/2a(t squared) If you don't have those you cannot find acceleration. However the acceleration on Earth is a constant -9.81
How do you find the time from acceleration and distance?
You can use the formula for distance covered:distance = (initial velocity) x (time) + (1/2) (acceleration) (time squared) Solve for time. This assumes constant acceleration, by the way. If you assume that the initial velocity is zero, then you can omit the first term on the right. This makes the equation especially easy to solve.
